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skelet666 [1.2K]
2 years ago
12

Graph the function f(x) = -3/5x+8.

Mathematics
1 answer:
emmasim [6.3K]2 years ago
6 0

Answer:

The y-intercept is at (0,8), so you can graph that point. Then the slope is -3/5. So the change in y coordinate divide the change in x coordinate is always -3/5. Thus 8-y/0-x=-3/5. You can choose any value for y and x as long as 8-y=-3. And 0-x=5. The point on the graph will just be (x,y) for the values you find.

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41 euros to 85 euros find the percent
Nitella [24]

Answer:

Step-by-step explanation:

1.21 United States Dollar

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2 years ago
Solve 2x+5 = 2x-3 for me <br> - thanks
Dima020 [189]

Answer:

2x+5=2x-3

2x-2x=-3-5

0=-8

Step-by-step explanation:

4 0
2 years ago
Suppose the sediment density(g/cm) of a randomly selected specimenfrom a certain region is normally distributed with mean 2.65 a
antiseptic1488 [7]

Answer:

ai )  P(\= X \le 3.0 ) =0.980

aii)  P(2.65 \le \= X  \le 3.00) =  0.480  

b )   n  =  32

Step-by-step explanation:

From the question we are told that  

     The mean is  \mu =  2.65

      The standard deviation is \sigma  =  0.85

Let the random  sediment density be  X

given that the  sediment density is normally distributed it implies that

      X  N(2.65 ,  0.85)

Now  probability that the sample average is  at 3.0 is mathematically represented as

        P(\= X \le 3.0 ) = P[\frac{\= X - \mu} {\frac{\sigma }{\sqrt{n} } } \le \frac{3.0 - \mu}{\frac{ \sigma}{\sqrt{n} } }  ]

Here n is the sample  size  = 25 and  \= X is the sample  mean  

  Now  Generally the  Z-value is obtained using this  formula  

           Z = \frac{\= X - \mu} {\frac{\sigma }{\sqrt{n} } }

Thus  

       P(\= X \le 3.0 ) = P[Z \le \frac{3.0 - 2.35}{\frac{ 0.85}{\sqrt{25} } }  ]

      P(\= X \le 3.0 ) = P[Z \le 2.06 ]

From the z-table the z-score is 0.980

 Thus  

       P(\= X \le 3.0 ) =0.980

Now  probability that the sample average is between 2.65 and 3.00  is  mathematically evaluated as

           P(2.65 \le \= X  \le 3.00) =  P [\frac{2.65 - \mu }{ \frac{\sigma }{\sqrt{n} } } < \frac{\= X - \mu }{ \frac{\sigma }{\sqrt{n} } }  <   \frac{3.0 - \mu }{ \frac{\sigma }{\sqrt{n} } }]  

          P(2.65 \le \= X  \le 3.00) =  P [\frac{2.65 - 2.65 }{ \frac{0.85 }{\sqrt{25} } }

         P(2.65 \le \= X  \le 3.00) = P[0 < Z< 2.06]    

       P(2.65 \le \= X  \le 3.00) =  P(Z < 2.06) - P(Z    

From the z-table  

        P(2.65 \le \= X  \le 3.00) =  0.980 - 0.50    

        P(2.65 \le \= X  \le 3.00) =  0.480  

Now  from the question  

         P(\= X \le 3.0 ) =0.99

=>       P(\= X \le 3.0 ) = P[Z \le \frac{3.0 - 2.35}{\frac{ 0.85}{\sqrt{n} } }  ] = 0.99

Generally the critical value of  z  for a one tail test such as the one we are treating that is  under the area  0.99  is  t_z  = 2.33 this is obtained from the critical value table  

So  

        t_z  = \frac{3.0 - 2.35}{\frac{ 0.85}{\sqrt{n} } }

        2.33  = \frac{3.0 - 2.35}{\frac{ 0.85}{\sqrt{n} } }

=>       n  =  32

4 0
3 years ago
Ashely walks 2 1/2 miles around a lake around three times a week. If Ashley walks around the lake in 3/4 hour,what is her rate o
Mashutka [201]
<span>To find Ashley's rate of speed in miles per hour, you will use the formula

Rate = Distance/Time.

First, you should fill in what you know. In this case, you know the distance is 2.5 miles, and the time is 0.75 hours. Now, you simply plug in the known variables to the formula to get Rate = 2.5 miles / 0.75 hours. After dividing, you reach the answer Rate = 3.333333 (or 3 and 1/3) miles/hour.</span>
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3 years ago
Under his cell phone plan, Damian pays a flat cost of $70 per month and $4 per
harkovskaia [24]

Answer:

g < 5

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He already uses $70 per month.

90-70=20

He has $20 left and each gigabyte is $4.

20/4=5

He can use 5 gigabytes while staying within his budget.

8 0
2 years ago
Read 2 more answers
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