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2 years ago

Graph the function f(x) = -3/5x+8.

Mathematics

1 answer:

emmasim [6.3K]2 years ago

6 0

Answer:

The y-intercept is at (0,8), so you can graph that point. Then the slope is -3/5. So the change in y coordinate divide the change in x coordinate is always -3/5. Thus 8-y/0-x=-3/5. You can choose any value for y and x as long as 8-y=-3. And 0-x=5. The point on the graph will just be (x,y) for the values you find.

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41 euros to 85 euros find the percent

Nitella [24]

Answer:

Step-by-step explanation:

1.21 United States Dollar

7 0

2 years ago

Solve 2x+5 = 2x-3 for me <br> - thanks

Dima020 [189]

Answer:

2x+5=2x-3

2x-2x=-3-5

0=-8

Step-by-step explanation:

4 0

2 years ago

Suppose the sediment density(g/cm) of a randomly selected specimenfrom a certain region is normally distributed with mean 2.65 a

antiseptic1488 [7]

Answer:

ai ) $P(\= X \le 3.0 ) =0.980$

aii) $P(2.65 \le \= X \le 3.00) = 0.480$

b ) $n = 32$

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 2.65$

The standard deviation is $\sigma = 0.85$

Let the random sediment density be X

given that the sediment density is normally distributed it implies that

X N(2.65 , 0.85)

Now probability that the sample average is at 3.0 is mathematically represented as

$P(\= X \le 3.0 ) = P[\frac{\= X - \mu} {\frac{\sigma }{\sqrt{n} } } \le \frac{3.0 - \mu}{\frac{ \sigma}{\sqrt{n} } } ]$

Here n is the sample size = 25 and $\= X$ is the sample mean

Now Generally the Z-value is obtained using this formula

$Z = \frac{\= X - \mu} {\frac{\sigma }{\sqrt{n} } }$

Thus

$P(\= X \le 3.0 ) = P[Z \le \frac{3.0 - 2.35}{\frac{ 0.85}{\sqrt{25} } } ]$

$P(\= X \le 3.0 ) = P[Z \le 2.06 ]$

From the z-table the z-score is 0.980

Thus

$P(\= X \le 3.0 ) =0.980$

Now probability that the sample average is between 2.65 and 3.00 is mathematically evaluated as

$P(2.65 \le \= X \le 3.00) = P [\frac{2.65 - \mu }{ \frac{\sigma }{\sqrt{n} } } < \frac{\= X - \mu }{ \frac{\sigma }{\sqrt{n} } } < \frac{3.0 - \mu }{ \frac{\sigma }{\sqrt{n} } }]$

$P(2.65 \le \= X \le 3.00) = P [\frac{2.65 - 2.65 }{ \frac{0.85 }{\sqrt{25} } }$

$P(2.65 \le \= X \le 3.00) = P[0 < Z< 2.06]$

$P(2.65 \le \= X \le 3.00) = P(Z < 2.06) - P(Z$

From the z-table

$P(2.65 \le \= X \le 3.00) = 0.980 - 0.50$

$P(2.65 \le \= X \le 3.00) = 0.480$

Now from the question

$P(\= X \le 3.0 ) =0.99$

=> $P(\= X \le 3.0 ) = P[Z \le \frac{3.0 - 2.35}{\frac{ 0.85}{\sqrt{n} } } ] = 0.99$

Generally the critical value of z for a one tail test such as the one we are treating that is under the area 0.99 is $t_z = 2.33$ this is obtained from the critical value table

$t_z = \frac{3.0 - 2.35}{\frac{ 0.85}{\sqrt{n} } }$

$2.33 = \frac{3.0 - 2.35}{\frac{ 0.85}{\sqrt{n} } }$

=> $n = 32$

4 0

3 years ago

Ashely walks 2 1/2 miles around a lake around three times a week. If Ashley walks around the lake in 3/4 hour,what is her rate o

Mashutka [201]

<span>To find Ashley's rate of speed in miles per hour, you will use the formula

Rate = Distance/Time.

First, you should fill in what you know. In this case, you know the distance is 2.5 miles, and the time is 0.75 hours. Now, you simply plug in the known variables to the formula to get Rate = 2.5 miles / 0.75 hours. After dividing, you reach the answer Rate = 3.333333 (or 3 and 1/3) miles/hour.</span>

8 0

3 years ago

Under his cell phone plan, Damian pays a flat cost of $70 per month and $4 per

harkovskaia [24]

Answer:

g < 5

Step-by-step explanation:

He already uses $70 per month.

90-70=20

He has $20 left and each gigabyte is $4.

20/4=5

He can use 5 gigabytes while staying within his budget.

8 0

2 years ago

Read 2 more answers