Answer:
import java.util.Scanner;
public class Solution {
public static void main(String args[]) {
Scanner scan = new Scanner(System.in);
int userNum = scan.nextInt();
if (userNum > 0) {
System.out.println("Positive.");
} else {
System.out.println("Non-positive, converting to 1.");
userNum = 1;
System.out.println("Final: " + userNum);
}
}
}
Explanation:
There was no error found when the code was run. The code segment was just added to a main method and it runs successfully.
Based on the full code above;
The first line import the Scanner class which allow the program to receive user input. Then the class was defined as Solution. Then the main method was defined. Inside the main method, we created a scanner object scan which receive the input via keyboard. The user input is assigned to the variable userNum. Then the if-conditional statement is executed; if userNum is greater than 0, "Positive" is output. Else userNum is converted to 1 and outputted to the screen.
Answer:
Moore's law predicts that this trend will continue into the foreseeable future.
Explanation:
Moore's Law refers to Moore's perception that the number of transistors on a microchip doubles every two years, though the cost of computers is halved.
Answer:
Packets can arrive out of order from the Internet Protocal layer. So,
when out-of-order packets with higher-than-expected sequence number arrives, then gap is detected.
Receiver of an out of order packet would then generate and sends a duplicate acknowledgement (ACK) for already received packet. If retransmission is performed after the first duplicate ACK, it would lead the sender to introduced too many redundant packets in the network.
Hence, TCP designer chose to wait for third acknowledgement (ACK) instead of performing a fast retransmission to avoid redundant packet transmission.
Answer: Internet Protocal (IP)
