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3 years ago

3 tickets to the museum cost $12.75. At this rate, what is the cost of:

Mathematics

2 answers:

Ksju [112]3 years ago

6 0

It’s $4.25. You would divide 12.75 by 3.00 to get your answer.

kumpel [21]3 years ago

4 0

I think the cost is 4.25

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Kristen invests $ 5745 in a bank. The bank 6.5% interest compounded monthly. How long must she leave the money in the bank for i

podryga [215]

Answer:

1. 10.7 years

2. 17.0 years

3. 2nd option

Step-by-step explanation:

Use formula for compounded interest

$A=P\cdot \left(1+\dfrac{r}{n}\right)^{nt},$

where

A is final value, P is initial value, r is interest rate (as decimal), n is number of periods and t is number of years.

In your case,

1. P=$5745, A=2P=$11490, n=12 (compounded monthly), r=0.065 (6.5%) and t is unknown. Then

$11490=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12t},\\ \\2=(1.0054)^{12t},\\ \\12t=\log_{1.0054}2,\\ \\t=\dfrac{1}{12}\log_ {1.0054}2\approx 10.7\ years.$

2. P=$5745, A=3P=$17235, n=12 (compounded monthly), r=0.065 (6.5%) and t is unknown. Then

$17235=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12t},$

$3=(1.0054)^{12t},$

$12t=\log_{1.0054}3,$

$t=\dfrac{1}{12}\log_{1.0054}3\approx 17.0\ years.$

3. 1 choice: P=$5745, n=12 (compounded monthly), r=0.065 (6.5%), t=5 years and A is unknown. Then

$A=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12\cdot 5},\\ \\A=5745\cdot (1.0054)^{60}\approx \$7936.39.$

2 choice: P=$5745, n=4 (compounded monthly), r=0.0675 (6.75%), t=5 years and A is unknown. Then

$A=5745\cdot \left(1+\dfrac{0.0675}{4}\right)^{4\cdot 5},\\ \\A=5745\cdot (1.0169)^{20}\approx \$8032.58.$

The best will be 2nd option, because $8032.58>$7936.39

5 0

3 years ago

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. You got 46 out of 65 questions right on your exam. What's your grade?

larisa86 [58]

Answer:

about like 8 /10

Step-by-step explanation:

8 0

3 years ago

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4. Look at these prices.

Snowcat [4.5K]

7.89 7.98 8.79 8.97

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3 years ago

Find all solutions of e^(e^z)=1

den301095 [7]

Start by reviewing your knowledge of natural logarithms. If we take the ln of both sides we get e^z=ln(1). Do the same thing again and wheel about the ln(ln(1)). There's going to be complex solutions, Wolfram Alpah gets them but let me know if you figure out how to do it?

8 0

3 years ago

A set X consists of all real numbers greater than or equal to 1. Use set-builder notation to define X.

vitfil [10]

Theory:

The standard form of set-builder notation is 

{ x | “x satisfies a condition” }

This set-builder notation can be read as “the set of all x such that x (satisfies the condition)”.

For example, { x | x > 0 } is equivalent to “the set of all x such that x is greater than 0”.

Solution:

In the problem, there are 2 conditions that must be satisfied:

1st: x must be a real number

In the notation, this is written as “x ε R”. Where ε means that x is “a member of” and R means “Real number”

2nd: x is greater than or equal to 1

This is written as “x ≥ 1”

Answer:

Combining the 2 conditions into the set-builder notation:

X = { x | x ε R and x ≥ 1 }

8 0

3 years ago

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