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3 years ago

There are 23 animals in the barn. Some are geese and some are cows. There are 80 legs in all. How many of each animal are there?

Mathematics

1 answer:

Ivan3 years ago

8 0

Answer:

17 cows and 6 geese

Step-by-step explanation:

1. set up two equations:

C + G = 23 (number of cows and geese = total number of animals)

4C + 2G = 80 (cows have 4 legs, geese have 2 legs and the total # of legs is 80)

2. 2(C+G)=2(23) ===> 2C + 2G = 46

3. subtract 4C + 2G = 80 and 2C + 2G = 46 to equal 2C=34, divide by 2 and C=17 (17 cows)

4. apply 17 back to the original (C + G = 23) equation to get: 17 + G = 23, subtract 17 from 23 and G=6 (6 geese)

i hope the way i explained it was clear! :)

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2 years ago

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x + y = 42, xy = 108 then what is x and y. Is there any (non-quadratic)formula for finding this instead of the process of elimin

charle [14.2K]

Answer:

when x = 39.25, y = 2.75

when x = 2.75, x = 39.25

Step-by-step explanation:

use substitution method

x+y = 42 ------ (1)

xy = 108 ------ (2)

from (1) ,

x+y = 42

y = 42-x ------ (3)

substitute (3) into (2)

xy = 108

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x² - 42x + 108 = 0

use the following formula to solve the value of x:

$i) \: x = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \: \\ ii) \: x = \frac{ - b - \sqrt{ {b}^{2} - 4ac } }{2a}$

a = 1

b = -42

c = 108

$i) \: x = \frac{ - b + \sqrt{ {b}^{2} - 4ac} }{2a}$

$x = \frac{ - ( - 42) + \sqrt{( - 42) {}^{2} - 4(1)(108)} }{2(1)}$

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$x = \frac{42 + \sqrt{1332} }{2}$

$x = \frac{42 + 6 \sqrt{37} }{2}$

$x = 21 + 3 \sqrt{37}$

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$ii) \: x \: \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a}$

$x = \frac{ - ( - 42) - \sqrt{( - 42) {}^{2} - 4(1)(108} }{2(1)}$

$x = \frac{42 - \sqrt{1764 - 432} }{2}$

$x = \frac{42 - \sqrt{1332} }{2}$

$x = \frac{42 - 6 \sqrt{37} }{2}$

$x = 21 - 3 \sqrt{37}$

$x = 2.75$

the 2 values of x are x = 39.25 and x = 2.75

substitute x = 39.25 into (3)

y = 42-x

y = 42-39.25

y = 2.75

substitute x = 2.75 into (3)

y = 42-x

y = 42-2.75

y = 39.25

when x = 39.25, y = 2.75

when x = 2.75, x = 39.25

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