Answer:
P ( z ) = 0.005
Step-by-step explanation:
From problem statement:
We know:
Researchers study 45 % adults over 65 suffering disorders
Sample 320 out of 750
then p = 320 / 750 = 0,4267
1.- Test hypothesis
H₀ null hypothesis ⇒ p₀ = 0,45
Hₐ alternative hypothesis ⇒ p₀ < 0.45
We calculate the z(s) as:
z(s) = ( p - p₀ )/ √ p₀*q₀/n ⇒ z(s) = ( 0.4267 - 0.45 )/ √(0.45*0,55)/750 z(s) = - 0.0233* √750 / 0.2475
z(s) = - 0.6381/0.2475 ⇒ z(s) = - 2.57
We look for - 2.57 in z tabl to find the probability of fewer than 320 out of 750 suffer of disorder, and find
P ( z ) = 0.0051
P ( z ) = 0.005
Suppose that the entire population of interest was eight students in a particular class. For a finite set of numbers, the population standard deviation is found by taking the square root of the average of the squared deviations of the values subtracted from their average value.
Answer:
m = -20
Step-by-step explanation:
first distribute:
-4(m + 18) = 8
-4m - 72 = 8
Now add 72 to both sides to get m by itself
-4m = 80
and divide by -4 on both sides
m = -20
Hope this helped! :)
1; 2×2; 3×3 ....6×6
6×6= 36