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ryzh [129]
3 years ago
6

Estimate -12 4/9 x 5 7/8

Mathematics
2 answers:
Tpy6a [65]3 years ago
8 0
The answer is 658\9
neonofarm [45]3 years ago
8 0

Answer:

-73\frac{1}{9}

Step-by-step explanation:

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Helppppp me plzzzzzzzzzzz
Iteru [2.4K]

Answer:

congruent

Step-by-step explanation:

4 0
3 years ago
HELPPPPPPP 1.The expression p−0.15p can be used to calculate the final cost of an item that has a price of p and is discounted 1
schepotkina [342]

Answer:

Answer is in the attachment

6 0
3 years ago
Given f(x)=2/5(6-x)^2 what is the value of f(6)?​
bulgar [2K]

Answer:

0

Step-by-step explanation:

f(x) = 2/5(6 - x)²

f(6) = 2/5[6 - (6)]²

f(6) = 2/5(0)²

f(6) = 0

5 0
3 years ago
A tank contains 1000 L of pure water. Brine that contains 0.05 kg of salt per liter of water enters the tank at a rate of 5 L/mi
Margaret [11]

Answer:

a) y(t)=0.65\frac{Kg}{min}(tmin)

b) y(40)=26Kg

Step-by-step explanation:

Data

Brine a (Ba)

V_{Ba}=5\frac{Lt}{min}\\  Concentration(Bca)=0.05\frac{Kg}{Lt}

Brine b (Bb)

V_{Bb}=10\frac{Lt}{min}\\  Concentration(Bcb)=0.04\frac{Kg}{Lt}

we have that per every minute the amount of solution that enters the tank is the same as the one that leaves the tank (15 Lt / min)

, then the amount of salt (y) left in the tank after (t) minutes: y=V_{Ba}*B_{ca}+V_{Bb}*B_{cb}=5\frac{Lt}{min}*0.05\frac{Kg}{Lt}+10\frac{Lt}{min}*0.04\frac{Kg}{Lt}=\\0.25\frac{Kg}{min}+0.4\frac{Kg}{min}=0.65\frac{Kg}{min}

Finally:

a) y(t)=0.65\frac{Kg}{min}(tmin)

b) y(40)=0.65\frac{Kg}{min}(40min)=26Kg

being y(t) the amount of salt (y) per unit of time (t)

5 0
3 years ago
4. What is one-half of 22,000?
Usimov [2.4K]

Answer:

11,000

Step-by-step explanation:

22,000 ÷ 2 = 11,000

8 0
2 years ago
Read 2 more answers
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