Question 2: At a swimming pool the ratio of those wearing sunscreen to

A national survey indicated that 50% of adults conduct their banking online. It also found that 20% are younger than 50, and

Arisa [49]

Answer:

The probability that a person is younger than 50 given that she uses onling banking is 1.5%

Step-by-step explanation:

The survey indicated that 50% of adults conducts their banking online.

P(online banking customers) =1/2

Of the total number of customer that bank online, the survey stated that 20% of them are younger than 50 years.

P(customers younger than 50 yrs) =1/5

Out of the 20% than are younger than 50, we were told that 15% of them conduct online banking.

P(younger than 50 online banking customer) =3/20

Therefore the the probability that a = person is younger than 50 given that she uses online banking is P = 3/20*1/5*1/2 =17==3/200 = 0.015 =1.5%

The probability that she is younger than 50 does not increase or decrease with additional information, it only makes it clearer.

3 0

4 years ago

Prove that the value of the expression does not depend on the variable x:

Leviafan [203]

Answer:

See below

Step-by-step explanation:

If an expression is not dependent on x, it simplified form must not contain x. To show that this is the case for (a) and (b) we need to simplify them and assess:

(a)

$(x-5)(x+8)-(x+4)(x-1)=\\=x^2-5x+8x-40-x^2-4x+x+4=-36$

Indeed, does not depend on x!

And (b)

$x^4-(x^2-1)(x^2+1)=x^4-x^4+x^2-x^2+1=1$

Again, does not depend on x.

8 0

3 years ago

{8, 15, 9, 18, 9, 17, 22, 10, 11, 9, 13}<br> What is the interquartile range of the data set?

8_murik_8 [283]

Answer:

IQR = 8

Step-by-step explanation:

The interquartile range (IQR) is the difference between the upper quartile Q₃ and the lower quartile Q₁

We require the data arranged in ascending order and to find the median Q₂

The median is the middle value of the data arranged in ascending order.

8, 9, 9, 9, 10, 11, 13, 15, 17, 18, 22

↑ Q₂

The upper quartile is the middle value of the data to the right of the median

13, 15, 17, 18, 22

↑ Q₃

The lower quartile is the middle value of the data to the left of the median

8, 9, 9, 9, 10

↑ Q₁

IQR = Q₃ - Q₁ = 17 - 9 = 8

6 0

3 years ago

- WILL GIVE BRAINLYEST

e-lub [12.9K]

Answer:

(a) II 1/1, 1/2, 1/3, 1/4, 1/5 I 2/1, 2/2, 2/3, 2/4, 2/5 I 3/1, 3/2, 3/3, 3/4, 3/5 I 4/1, 4/2, 4/3, 4/4, 4/5 I 5/1, 5/2, 5/3, 5/4, 5/5 II

(b) 9/25

(c) You would expect 2 more because 9 out of 25 you should get a 4, and the math is, 100 / 24 = 4 I 9 x 4 = 36.

Step-by-step explanation:

I took the K12 test, and don't copy paste this answer pls.

6 0

3 years ago

A fence is to be built to enclose a rectangular area of 800 square feet. The fence along three sides is to be made of material t

myrzilka [38]

Answer:

dc/dx = 0 when x = 20. hence fence is 20×40

Step-by-step explanation:

Given data:

Rectangular Area = 800 ft^2

three side material cost = $5 per ft

fourth side material cost is $15 per ft

let expensive side is x and other dimension assume to be y

Then cost is c

c = 5(x+ 2y) + 15 x

xy = 800, so y = 800/x

c =5(x+ 1600/x^2) + 15x

for minimum when dc/dx = 0

$\frac{dc}{dx} = 5(1-\frac{1600}{x^2}) + 15 = 0$

$5(1-\frac{1600}{x^2}) + 15 = 0$

$(1-\frac{1600}{x^2}) + 3 = 0$

$(1-\frac{1600}{x^2}) = - 3$

$x^2 - 1600 = -3x^2$

$4x^2 - 1600 = 0$

(2x-40)(2x+40) = 0

x = 20

dc/dx = 0 when x = 20. hence fence is 20×40

3 0

4 years ago