All categories

3 years ago

BRAINLEST+THANKS!! Thank uu

Mathematics

2 answers:

saul85 [17]3 years ago

8 0

Answer:

I'm gonna try. x = 7.71428571429???? I honestly have no idea since im not at this stuff yet.

Step-by-step explanation:

azamat3 years ago

6 0

Answer:

hiiii

the question isn't seen clearly

You might be interested in

11-18 please help with work shown I’m lost completely

Ray Of Light [21]

Answer:

11. A)45°

12. A)45°

13. A)45°

14. B)180°

15. C)65°

16.D)135°

17. A)115°

18. B)180°

Step-by-step explanation:

An arc measure is defined as the measure of an angle an arc creates in a circle's center.

11.#from properties of a circle, we know arcs of a circle are proportional to their corresponding angle

$\angle DXB=arc \ DC\\\\45\textdegree=arc \ DC$

Hence, the arc measure DC is 45°

12.#from properties of a circle, we know arcs of a circle are proportional to their corresponding angle

Let x be the center of the circle;

$\angle AXB=arc \ AB\\\\45\textdegree=arc \ AB$

Hence, the arc measure AB is 45°

13. Given BE is a diameter, we know from properties of a circle that the angle subtending it is equal to 180°.

$\angle BXE=\angle BXA+\angle AXE=180\textdegree\\\\\angle AXE=180\textdegree-45\textdegree\\\\=135\textdegree$

Also, given AD is a diameter:

$\angle AXD=\angle EXD+\angle AXE=180\textdegree\\\\\angle EXD=180\textdegree-135\textdegree\\\\=45\textdegree$

Hence, the arc measure ED is 45°

14.Given AD is a diameter, we know from properties of a circle that the angle subtending it is equal to 180°.

Hence, the arc measure ABD is 180°

15. Given AD is a diameter, we know from properties of a circle that the angle subtending it is equal to 180°.

$\angle AXD=\angle AXB+\angle BXC+\angle CXD=180\textdegree\\\\\angle BXC=180\textdegree-45\textdegree-70\textdegree\\\\=65\textdegree$

Hence, the arc measure BC is 65°

16. #from properties of a circle, we know arcs of a circle are proportional to their corresponding angle:

$\angle BXD=\angle BXC+\angle CXD=\\\\\angle BXD=70\textdegree+65\textdegree\\\\=135\textdegree$

Hence, the arc measure BD is 135°

17. From a3 above, we know the arc measure ED is 45°. The arc measure of CED is equivalent to ED plus CD:

$\angle CED=\angle DXE+\angle CXD=\\\\\angle BXD=70\textdegree+45\textdegree\\\\=115\textdegree$

Hence, the arc measure CED is 115°

18.Given AD is a diameter, we know from properties of a circle that the angle subtending it is equal to 180°.

Hence, the arc measure ADB is 180°

8 0

4 years ago

Avery is tracking the height of a plant that grows at a constant rate. After the third week, the plant is 8.5 centimeters high.

Vadim26 [7]

Answer:

Original Plant was 1cm and it grew 2.5 cm per week.

Step-by-step explanation:

Using the Slope Formula (y2-y1/x2-x1)we can get how many centimeters it will grow in a week.

18.5cm-8.5cm/7-3

10cm/4

2.5 cm per week.

3 0

3 years ago

A company manufactures 2,000 units of its flagship product in a day. The quality control department takes a random sample of 40

shepuryov [24]

Answer:

Step-by-step explanation:

The recommended sample size n for point estimates is:

n = NX / (N + X - 1)

where N is the population size, and X is defined as:

X = Z² p (1 - p) / E²

where Z is the critical value, p is the sample proportion, and E is the margin of error.

Assume a confidence level of level of 95% and a margin of error of 5%.

α = 0.05, Z(α/2) = 1.96

E = 0.05

Of the 40 units tested, 2 had lifespans less than 26 days. So the proportion is:

p = 2/40 = 0.05

Therefore:

X = (1.96)² (0.05) (1 - 0.05) / (0.05)²

X = 73

Given N = 2000:

n = (2000) (73) / (2000 + 73 - 1)

n = 70.45

Rounding, the recommended sample size is 70.

5 0

4 years ago

Read 2 more answers

Could someone please help?

kolezko [41]

Answer:help you with what?

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

Please help me with the below question.

denpristay [2]

Since $G$ is a group,

• $G$ has an identity element $e$ such that $ae=ea=a$ for all $a\in G$

• there is an inverse $a^{-1}$ for every $a\in G$ such that $aa^{-1}=a^{-1}a=e$

• for any $a,b,c\in G$ , we have the associative property $a(bc)=(ab)c=abc$

a) Given that $a^3 b = b a^3$ , we have

$a^3 b = b a^3 \implies a^2 (a^3 b) = a^2 (b a^3) \implies a^5 b = a^2 b a^3$

Since $|a|=5$ , which means $a^5=e$ , we get that

$b = a^2 b a^3$

Then

$a b = (a^3 b) a^3 = (b a^3) a^3 = b a^6 = b a^5 a = b a$

as required.

b) What do you mean by "rank of an element in a group"? That doesn't sound like a standard concept as far as I know.

5 0

2 years ago