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Oxana [17]
3 years ago
14

Find the slope of the line.. pls help me ill give brainliest. Its timed.

Mathematics
1 answer:
dusya [7]3 years ago
4 0

Answer:

-1/1

Step-by-step explanation:

Good Luck

~theLocoCoco

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Simplify: - 4x 5x - 1 + 3-6x 3-6x​
Vitek1552 [10]

Answer:

−45−1+3−63−6

−46−1+3−63−6

−46+2−63−6

Solution:

−46−63−6+2

Step-by-step explanation:

I hope that this is what you are looking for

Have a nice day/night

3 0
3 years ago
What number complete the fallowing equation? 8×(40+7)=(8×_)+(8×7) A=40 B=47 C=320 D =376
11Alexandr11 [23.1K]

8x40=320 (+) 8x7=56 (=) 376.

A=40

hope this helped


3 0
3 years ago
Read 2 more answers
Adidea Corp regularly buts merchandise from vendors. It just purchased 1,000 units on credit from one of its vendors. How will t
Lostsunrise [7]

Answer:

You did not include the price they bought the units at.

I will assume this price is $5.

= 5 * 1,000

= $5,000

Recording it will be:

    Account                                                           Debit                     Credit

    Merchandise Inventory                                 $5,000

          Accounts Payable                                                                 $5,000

7 0
2 years ago
What is the slope of this line?
kumpel [21]

Answer:

1/2 maybe

Step-by-step explanation:

4 0
3 years ago
Which equation describes a line that passes through (-6, 8) and is parallel to the line described by y = 2x − 4?
AleksandrR [38]

Answer:

hey, there!

Step-by-step explanation:

The given is a point (-6,8) through which a line passes. And is perpendicular to the line y = 2x-4

The equation for point (-6,8) is,

(y-8)= m1(x+6)...........(i)

and given equation is y = 2x-4............(ii)

Now, from equation (ii).

slope (m2)= 2 { as equation (ii) is in the form of y= mx+c where m is a slope}.

Now, For perpendicular,

m1×m2= -1

m1×2= -1

Therefore, m1 = -1/2.

Putting, the value of m1 in equation (i).

(y-8) = -1/2×(x+6)

2(y-8)= -1(x+6)

2y - 16 = -x -6

x+2y-10 = 0......... is the required equation.

Hope it helps...

6 0
2 years ago
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