Answer:
Option B
Step-by-step explanation:
Given quadratic equation is,
12a² + 9a + 7 = 0
By comparing this equation with standard quadratic equation,
hx² + kx + c = 0
h = 12, k = 9 and c = 7
By using quadratic formula,
a = 
= 
= 
= 
= 
a = 
Therefore, Option B will be the correct option.
First we find the common difference...to do this we subtract the first term from the second term. -7 - (-1) = -7 + 1 = -6
now we are going to find the 10th term
an = a1 + (n-1)*d <== formula for finding any term in arithmetic series
a1 = 1st term, d = common difference, n = term we want to find
now we sub
a10 = -1 + (10 -1) * -6
a10 = -1 + (9 * -6)
a10 = -1 - 54
a10 = - 55
now we will find the sum
Sn = (n (a1+ an)) / 2 <== formula for finding the sum
S10 = (10(-1 - 55))/2
S10 = (10(-56) / 2
S10 = -560/2
S10 = - 280
so the sum of the first 10 numbers is -280
Answer: B. 0.25, 3.75, 5.2
Step-by-step explanation:
Since, the given sequence, 
And, 
On substituting n=5 in the given recursive formula,
We get, 
For, n=4 
For, n=3 
For, n=2 
Thus, First second and third terms are,
,
and
.