Which is not equivalent to Ax + By=C?

Gabriel is making a mixture of compost and soil to use for a special plant. He wants his final mixture to be 2 parts compost to

ICE Princess25 [194]

2parts compost and 10pats potting soil
2/10=1/5 which is 1 to 5 ratio.
He wants to end up with 6 kilograms which is 1 kg compost and 5kg of plotting soil.so he can use 1 kg compost
hope it helps

4 0

3 years ago

39 s 150% of what number?

professor190 [17]

Answer:

26

Hope this helps!

6 0

3 years ago

a 30% sugar syrup is mixed with 10% sugar syrup.The result is 600 g of 15% sugar syrup. How many grams of each syrup are in the

labwork [276]

Answer:

450g of 10% sugar syrup

150g of 30% sugar syrup

Step-by-step explanation:

3 0

3 years ago

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The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price

inn [45]

Answer:

Product A has a greater percentage change in price.

Step-by-step explanation:

Part A:

The price f product A, f (x) after x years is given by:

$f(x) = 0.69\cdot(1.03)^{x}$

After x = 0 years, the price of product A is:

$f(0) = 0.69\cdot(1.03)^{0}=0.69$

After x = 1 years, the price of product A is:

$f(1) = 0.69\cdot(1.03)^{1}=0.69\cdot (1+0.03)=0.69\cdot (1+3\%)$

After 1 year, the price of product A is 3% times more than the original price.

This means that after one year, the new price is 103% of the original price, which means the price product A is increasing by 3%.

Again after x = 2 years, the price of product A is:

$f(2) = 0.69\cdot(1.03)^{2}=[0.69\cdot (1+3\%)]\times (1.03)$

This implies that after 2 years, the price of product A is 103% of the price after year 1.

This implies that the price of product A is 3% more than the previous year.

Thus, the price of product A is increasing each year by 3%.

Part B:

The data for Product B is as follows:

Time (t) Price [f (t)]

1 10,100

2 10,201

3 10,303.01

4 10,406.04

Product B is clearly increasing in price.

Consider the changes in price of Product B in the following intervals of years:

Year 1 - Year 2:

Price in year 1 = $10,100

Price in Year 2 = $10,201

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10201-10100}{10100}=0.01=1\%$

Year 2 - Year 3:

Price in Year 2 = $10,201

Price in year 3 = $10,303.01

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10303.01-10201}{10201}=0.01=1\%$

Year 3 - Year 4

Price in year 3 = $10,303.01

Price in Year 4 = $10,406.04

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10,406.04-10303.01}{10303.01}=0.09999\approx 0.01=1\%$

It is quite clear that the price of product B increases by 1% each year.

Thus, Product A has a greater percentage change in price.

3 0

3 years ago

12 is 30% of ____ (Please explain)

natka813 [3]

Answer:

40

Step-by-step explanation:

In word problems, the word "of" usually means multiply. Thus, for example, 10% of $50 is $5. This is because we can write 10% as 0.10 or as 10/100 (which is 1/10) and then multiply: (1/10)(50) = 5

So, we often see equations like:

R = (1/2)D meaning R is 50% of D, or R is half of D

Let x = the number we want to find

This problem says:

"12 is 30% of what number?"

12 = (30/100) * x

12 = (3/10)x

(10/3)12 = x [multiply both sides by (10/3)]

40 = x

Checking (very important):

Is 12 = (3/10)(40) ?

12 = (3)(4) ?

12 = 12 ? yes

7 0

2 years ago

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