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cestrela7 [59]
2 years ago
7

The 7th term of an A.p is -4. If the common difference is-5, find the 6th term​

Mathematics
1 answer:
Lubov Fominskaja [6]2 years ago
7 0

Answer:

Step-by-step explanation:

a₆ = a₇+(6-7)d = -4 -(-5) =1

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Nate invests $1,000 into an account with a 5.2% interest that is compounded annually. How much money will he have in this accoun
Naily [24]

Answer:

In 5 years, you will have $1,288.48

Step-by-step explanation:

6 0
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What is the solution to 3x²+x+10=0
e-lub [12.9K]

Answer:

x = - 1/6 + √-119/6, and, - 1/6 - √-119/6

Step-by-step explanation:

Using the quadratic formula which is: - b ± √b² - 4ac / 2a

a = 3, b = 1, c = 10

- 1 ± √1² -4 * 3 * 10 / 2 * 3

- 1 ± √1 - 120 / 6

-1 ± √-119 / 6

= -1/6 + √119/6,               or                  - 1/6 - √-119/6

7 0
3 years ago
Can someone help me please. I can give you extra points. Message me or text me on snap anja4life. To help me with more please
Tju [1.3M]
<h3>Answer:  8</h3>

=====================================

Work Shown:

y = 192\left(4^{x-3}\right)\\\\196,608 = 192\left(4^{x-3}\right)\\\\\frac{196,608}{192} = 4^{x-3}\\\\1024 = 4^{x-3}\\\\4^{x-3} = 1024\\\\\log\left(4^{x-3}\right)=\log\left(1024\right)\\\\(x-3)*\log\left(4\right)=\log\left(1024\right)\\\\x-3=\frac{\log\left(1024\right)}{\log\left(4\right)}\\\\x-3=5\\\\x=5+3\\\\x=8\\\\

It will take 8 hours for the population to reach 196,608 bacteria.

3 0
2 years ago
Dave has $8000 to invest for 15 years. He finds a bank that offers an interest rate of 3.1% compounded monthly. How much money w
ioda

Dave will have $12,728 after 15 years, if he has $8000 to invest for 15 years. He finds a bank that offers an interest rate of 3.1% compounded monthly.

Step-by-step explanation:

The given is,

                 Investment = $ 8000

               No. of years = 15 years

             Interest rate, i = 3.1 %

                 ( compounded monthly )  

Step:1

          For for calculating future value with compound interest monthly,

                                     A = P (1 +\frac{r}{n})^{nt}.................(1)

         Where,

                     A = Future amount

                     P = Initial investment

                     r = Rate of interest

                    n = Number of compounding in a year

                     t = Time period

Step:2

           From given values,

                           P = $8000

                            r =  3.1%

                            t = 15 years

                            n = 12 ( for monthly)

           Equation (1) becomes,

                          A = 8000( 1+\frac{0.031}{12} )^{(12)(15)}

                              = 8000 (1+0.002583)^{180}

                              = 8000(1.002583)^{180}

                              = 8000(1.591059)

                              =12728.48

                           A = $ 12728.48

Result:

           Dave will have $12,728 after 15 years, if he has $8000 to invest for 15 years. He finds a bank that offers an interest rate of 3.1% compounded monthly.

                             

       

8 0
3 years ago
What the error to this promblem
dimaraw [331]
The error to that problem is the person switched the x and y points, like in point A, it’s supposed to be (x,y) or (1,5). The person put the y in front of the x while writing the points.
3 0
2 years ago
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