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Tcecarenko [31]
2 years ago
7

This is so important please help

Mathematics
1 answer:
Shtirlitz [24]2 years ago
3 0

Given:

The center of the circle = (-1,0)

Point on the circle = (2,-4).

To find:

The equation of the circle.

Solution:

Distance between two points is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between the center (-1,0) and the point on the circle (2,-4) is the radius of the circle.

r=\sqrt{(2-(-1))^2+(-4-0)^2}

r=\sqrt{(2+1)^2+(-4)^2}

r=\sqrt{(3)^2+(-4)^2}

On further simplification, we get

r=\sqrt{9+16}

r=\sqrt{25}

r=5

Now, the equation of the circle is

(x-h)^2+(y-k)^2=r^2

Where, (h,k) is the center and r is the radius of the circle.

The radius of the circle is 5 and the center is at (-1,0), so the equation of the circle is

(x-(-1))^2+(y-0)^2=5^2

(x+1)^2+y^2=25

Therefore, the first option is correct, i.e., (x+1)^2+y^2=25.

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