Answer is unlikely.
Hope it helps!
The length and width of the rectangle is 11 in and 8 in respectively.
Step-by-step explanation:
Given,
The width of a rectangle is 3 in less than the length.
The area of each congruent right angle triangle = 44 in²
To find the length and width of the rectangle.
Formula
The area of a triangle with b base and h as height =
bh
Now,
Let, the width = x and the length = x+3.
Here, for the triangle, width will be its base and length will be its height.
According to the problem,
×(x+3)×x = 44
or, 
or,
or,
+(11-8)x-88 = 0
or,
+11x-8x-88 =0
or, x(x+11)-8(x+11) = 0
or, (x+11)(x-8) = 0
So, x = 8 ( x≠-11, the length or width could no be negative)
Hence,
Width = 8 in and length = 8+3 = 11 in
m<1=152
m<2=28
m<3=152
m<4=28
m<5=152
m<6=28
m<7=152
not completly sure but good luck
I’m retailing there is a direct interaction with the answer is all of the above
Answer:
Step-by-step explanation:
144 = -16t² + 151t + 95
0 = -16t² + 151t - 49
quadratic formula
t = (-151 ±√(151² - 4(-16)(-49))) / (2(-16))
t = (-151 ± 140.23195) / -32
t = 0.34 s
t = 9.10 s