Answer:
Step-by-step explanation:
Find the image attached. For two triangles to be congruent, then the sides of UVW is equal to that of TSR
From the diagram given
TR = UW
Given
TR = 50
UW = 3z+14
Equate and find z;
3z+14 = 50
3z = 50-14
3z = 36
z = 36/3
z = 12
VW = RS
Given
VW = 27
RS = 5y - 33
Equate
5y-33 = 27
5y = 27+33
5y = 60
y = 60/5
y = 12
Also TS = UV
TS = 53
UV = 12x+7
Equate:
12x-7 = 53
12x = 53+7
12x = 60
x = 60/12
x = 5
Hence x = 5, y = 12 and z = 12
radius = 12/2
r = 6ft
diameter is given
diameter = 12ft
formula for circumference = 2πr
formula for area = πr²
circumference = 264/7
= 37.714 ft
We have a segment, for which we know one endpoint T=(2,4) and the midpoint M=(3, 6.5).
We have to find the other endpoint, lets call it S.
Both for the x-coordinates and y-coordinates the distance in each axis from T to M (TM) has to be equal to the distance M to S (MS).
Then, if we look at the x-axis, we have that the distance is TMx=2-3=-1.
Then, S has to be one unit above M: the x-coordinate of S is xS=4.
We do the same for the y-axis. The distance TMy is TMy=4-6.5=-2.5.
Then, S has to be 2.5 units above M: the y-coordinate of S is yS=(6.5+2.5)=9.
The coordinates of S are (4,9).
Graph:
