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2 years ago

11

Solve for 7/2x+7/9x=−17+2/56

1 answer:

kati45 [8]2 years ago

4 0

Answer:

7/2x+7/9x-(-17+25/6)=0

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2 years ago

What are the roots of the quadratic equation 2x2+7x+4=0? Select all that apply.

skad [1K]

Answer:

option A and B

$x=\frac{-7+\sqrt{17}} {4}$

and

$x=\frac{-7-\sqrt{17}} {4}$

Step-by-step explanation:

we have

$2x^2+7x+4=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^2+7x+4=0$

so

$a=2\\b=7\\c=4$

substitute in the formula

$x=\frac{-7\pm\sqrt{7^{2}-4(2)(4)}} {2(2)}$

$x=\frac{-7\pm\sqrt{17}} {4}$

so

$x=\frac{-7+\sqrt{17}} {4}$

and

$x=\frac{-7-\sqrt{17}} {4}$

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2 years ago