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2 years ago

What data does the x-axis show? 25 points ***!!

Mathematics

1 answer:

Aleonysh [2.5K]2 years ago

6 0

Answer:

time in weeks

Step-by-step explanation:

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(4w-3)^2 what would be the answer to that?? please explain, i’m so confused.

yarga [219]

Answer:

16w^2 - 24w + 9

Step-by-step explanation:

To simplify this, you would use the special product (a - b)^2 = a^2 - 2ab + b^2. We can correlate this with the given term so that,

a = 4w

and

b = 3

Now we just substitute into a^2 - 2ab + b^2

(4w)^2 - 2(4w)(3) + (3)^2

16w^2 - 24w + 9

7 0

3 years ago

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Which of the following is a source of income?

Sav [38]

Answer:

B. Invesment

Correct me if You want If its wrong.

8 0

2 years ago

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Area of 100 3/4 feet x 75 1/2 feet?

kaheart [24]

100 3/4 x 75 1/2
25 x 3 x 75 1/2. (Divided by 4 to 100 and 4 to get 25)

25 x 3 x 75 1/2 ( multiple everything on top)

5625/2 ( then divided normally)

2812.5 or 2812 1/2

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3 years ago

Stress at work: In a poll conducted by the General Social Survey, 81% of respondents said that their jobs were sometimes or alwa

andrew-mc [135]

Answer:

We are given that 81% of respondents said that their jobs were sometimes or always stressful.

So, p = 0.81

(a) Approximate the probability that 150 or fewer workers find their jobs stressful.

x = 150

p = 0.81

n = 175

So, $\frac{x}{n} =\widehat{p}$

$\frac{150}{175} =\widehat{p}$

$0.8571=\widehat{p}$

Formula : $z=\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}$

$z=\frac{0.8571-0.81}{\sqrt{\frac{0.81(1-0.81)}{175}}}$

$z=1.5882$

Refer the z table

So, P(z<150)=0.9429

So, the probability that 150 or fewer workers find their jobs stressful is 0.9429

b) Approximate the probability that more than 140 workers find their jobs stressful.

x = 140

p = 0.81

n = 175

So, $\frac{x}{n} =\widehat{p}$

$\frac{140}{175} =\widehat{p}$

$0.8=\widehat{p}$

Formula : $z=\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}$

$z=\frac{0.8-0.81}{\sqrt{\frac{0.81(1-0.81)}{175}}}$

$z=-0.3372$

P(z<140) = 0.3707

P(z>140)=1-P(z<140)=1-0.3707=0.6293

So, the probability that more than 140 workers find their jobs stressful is 0.6293

c) Approximate the probability that the number of workers who find their jobs stressful is between 146 and 150 inclusive.

x = 146

p = 0.81

n = 175

So, $\frac{x}{n} =\widehat{p}$

$\frac{146}{175} =\widehat{p}$

$0.8342=\widehat{p}$

Formula : $z=\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}$

$z=\frac{0.8342-0.81}{\sqrt{\frac{0.81(1-0.81)}{175}}}$

$z=0.816$

From part a) P(z<150)=0.9429

So,P(z<150)-P(z<146)=0.9429 - 0.8342=0.1087

Hence the probability that the number of workers who find their jobs stressful is between 146 and 150 inclusive is 0.1087

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3 years ago

A patrol man gives a driver speeding ticket if the driver speed is greater than 15% over the posted speed limit . If the speed l

Maru [420]

10%of 40=4 5% of 40=2 4+2=6 40+6=46 so the answer is 46mph

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3 years ago

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