1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
baherus [9]
3 years ago
12

Please look at the picture!

Mathematics
2 answers:
diamong [38]3 years ago
8 0

Answer:

Answer= A- 7%

Step-by-step explanation:

42/100= 42%

35/100= 35%

42%-35%= 7%

belka [17]3 years ago
6 0

Answer:

It's A my friend

Step-by-step explanation:

You might be interested in
Can someone answer this please!!!
Sergeeva-Olga [200]

Answer:

y= -1/4 x+4

Step-by-step explanation:

1. Solve for y

2. Use the same equation you just got without the 7 (b value) and plug in the new point (8,2) into the x and y

3. Solve for b

4. Final equation includes the slope found in step 1 and the new b value

6 0
3 years ago
pls pls pls help i give brainest and i will give 37 points and i will give a thanks plssss sove 22 and 23
Alex787 [66]
<h2>Answer:</h2><h2>what do u mean solve 22&23</h2>

8 0
2 years ago
Please help with this Piecewise problem!!
tino4ka555 [31]

Remark

That was well worth doing. Desmos gave you the answer to the graph. Unfortunately I can only give you the correct graph. You will have to figure out from the choices which one is the correct answer -- or edit it so I can see what the rest of the question is.

Graph

The red one is f(x) is x + 3 {x <= -2}

The blue one is f(x) is x^2 - 1 {-2 <x <1} Notice the gap at 2. It is not continuous

The green one is f(x) is log_2(-x + 3)  {1 <=x < 3} and there is a gap between the blue and green one.

4 0
3 years ago
What is the solution to the equation 41/5 =15-(2x+3)
likoan [24]
\frac{41}{5}=15-(2x+3) \\\\ \frac{41}{5}=15-2x-3 \\\\ \frac{41}{5}=12^{(5}-2x^{(5} \\\\ 41=60-10x \\\\ 41-60=-10x \\\\ -19=-10x \\\\ 19=10x \\\\ \boxed{x=\frac{19}{10}}
4 0
3 years ago
Read 2 more answers
Warren brought $41.50 to the art supply store. He bought a brush, a sketchbook, and a paint set. The brush was 1 6 as much as th
melomori [17]

Answer:

Warren paid $2.5 for the brush, $15 for the sketchbook and $20 for the paint set.

Step-by-step explanation:

If Warren went to the store with $41.5 and left with only $4 then the total amount he spent on the store was:

total spent = 41.5 - 4 = 37.5

Since he bought a brush, a sketchbook and a paint set we have:

brush + sketchbook + paint = 37.5

The prices of each item are related in the following manner:

brush = (1/6)*sketchbook

sketchbook = (3/4)*paint

brush = (1/6)*(3/4)*paint = (3/24)*paint = (1/8)*paint

Using these expressions on the one that represents the total value we will be abble to have only one variable, paint. We have:

(1/8)*paint + (3/4)*paint + paint = 37.5

(1/8)*paint + (6/8)*paint + (8/8)*paint = 37.5

(15/8)*paint = 37.5

paint = 37.5/(15/8) = 37.5*(8/15) = 20

brush = (1/8)*paint = (1/8)*20 = 2.5

sketchbook = (3/4)*paint = (3/4)*20 = 15

Warren paid $2.5 for the brush, $15 for the sketchbook and $20 for the paint set.

6 0
3 years ago
Read 2 more answers
Other questions:
  • There are seven days in a week. How many days are there in 16 weeks?
    11·2 answers
  • Question 6 of 10
    10·1 answer
  • The CEO of Millennium Dairy Product, a small venture among 10 partners each having 100,000 shares, sought to raise an additional
    5·1 answer
  • What is the formula for volume of a cylinder​
    10·2 answers
  • I need help I will give brainiest​
    9·1 answer
  • On Saturday, 4 groups of people went to the restaurant at the ski resort. Each group had 5 people in it. Everyone ordered a cup
    13·1 answer
  • Please please help me meeeee please
    13·2 answers
  • Ecan someone plase help me on this
    8·1 answer
  • A mixture of purple paint contains 6 teaspoons of red paint and 15 teaspoons of blue paint. To make 35 teaspoons of purple paint
    6·2 answers
  • I dont get this can someone help me pls​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!