Answer:
Simplifying
lx2 + mx + n = 0
Solving
lx2 + mx + n = 0
Solving for variable 'l'.
Move all terms containing l to the left, all other terms to the right.
Add '-1mx' to each side of the equation.
lx2 + mx + -1mx + n = 0 + -1mx
Combine like terms: mx + -1mx = 0
lx2 + 0 + n = 0 + -1mx
lx2 + n = 0 + -1mx
Remove the zero:
lx2 + n = -1mx
Add '-1n' to each side of the equation.
lx2 + n + -1n = -1mx + -1n
Combine like terms: n + -1n = 0
lx2 + 0 = -1mx + -1n
lx2 = -1mx + -1n
Divide each side by 'x2'.
l = -1mx-1 + -1nx-2
Simplifying
l = -1mx-1 + -1nx-2
Step-by-step explanation:
Hope this helped you!
Trapezoid:
•Can have congruent diagonals. •Has one pair of opposite, parallel sides.
Kites:
•Has congruent adjacent sides.
•Has perpendicular diagonals.
Answer:
5
Step-by-step explanation:
Let the smallest integer equal x - 1, the next one equal x, and the last one equal x + 1.
4(x-1) = 3(x-1) + 6
x-1 = 5
x = 6
The smallest integer is x - 1, which is equal to 5. Thus, the smallest of the three integers is 5.
Answer:
number 4 i gess
Step-by-step explanation:
