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soldi70 [24.7K]
2 years ago
15

If 3/4 of the 12 pencils were sharpened, then how many pencils were sharpened?

Mathematics
2 answers:
musickatia [10]2 years ago
6 0
12/4= 3. 3x3=9. 9 of them were sharpened
Mandarinka [93]2 years ago
6 0

Answer:

9 pencils were sharp

Step-by-step explanation:

3*4=12 so if three fourths were sharp then 9 were

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Simplify the expression by combining like terms.
Tju [1.3M]

Answer:

8x + 13

Step-by-step explanation:

"Like terms" means the same kind of algebraic expression...the 6x and the 2x are "like terms" because they both have an x in them. The 9 and the 4 are both constants, which means they are plain numbers. So 6x and 2x is 8x .

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4 0
2 years ago
How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi
ryzh [129]

<u>Answer</u>:

3003 number of 5-member chess teams can be chosen from 15 interested players.

<u>Step-by-step explanation:</u>

Given:

Number of the interested players =  15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formulanCr = \frac{n!}{r!(n - r)!}

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now  we have n = 15 and r = 5

Substituting the values,

15C_5 = \frac{15!}{5!(15- 5)!}

15C_5 = \frac{15!}{5!(10)!}

15C_5 = \frac{15!}{5!(10)!}

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15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}

15C_5 = \frac{360360}{120}

15C_5 = 3003

7 0
3 years ago
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