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3 years ago

Help help please thanks

Mathematics

1 answer:

Leto [7]3 years ago

5 0

Answer:

x = 16

4x = 64

Step-by-step explanation:

The sum of the exterior angles of any polygon is 360°

Add the given angles and solve for x

93 + 46+ 3x + 62 + 4x +47 = 360

7x + 248 = 360

7x = 360 –248

x = 16

4(16) = 64

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Factor completely. 486 + 108z + 6x2 =

Firlakuza [10]

Answer:

6(x^2 +18z +81) . . . as written
6(x +9)^2 . . . . . . . . assuming a typo

Step-by-step explanation:

As the expression is written, the only factoring that can be done is to factor out the common numeric factor of 6:

= 6(x^2 +18z +81)

Assuming a typo in the question

If we assume all variables are supposed to be "x", then the quadratic term can be further factored as a square:

= 6(x +9)^2

_____

It is often handy to remember that the form of the square of a binomial is ...

(a +b)^2 = a^2 +2ab +b^2

Here, we recognize that 18 = 2√81, so the binomial is (x +√81) = (x +9).

7 0

3 years ago

Pls help number 8 only Pythagorean theorem

o-na [289]

Answer:

8. a = 30

9. a = 3.46

General Formula:

a = square root c^2 - b^2

8 0

3 years ago

Alexa works for an ice cream cart vendor . She receives $28 for taking the cart out for a shift plus a commission of $0.15 for e

zimovet [89]

Answer:

28 + 0.15x = 49.30

0.15x = 49.30 - 28

0.15x = 21.3

divide both sides by 0.15

x = 21.3/0.15

x = 142

5 0

3 years ago

Consider the function f(x)=9-x^2/x^2-4 For which intervals is f(x) positive? Check ALL that apply.

solong [7]

Answer:

a. f (x) < 0 for x ∈ (-∞ ,-3)

b. f (x) > 0 for x ∈ (-3,-2)

c. f (x) < 0 for x ∈ (-2,2)

d. f (x) > 0 for x ∈ (2,3)

e.f (x) < 0 for x ∈ (3,∞)

Step-by-step explanation:

Here, the given function is: $f(x)= \frac{9-x^2}{x^2-4}$

Now, to check for the sign of f(x) at x = k, put the value of x from the given interval.

We get:

a. (-infinity, -3)

put k = -4 from the given interval

We get $f(-4)= \frac{9-(-4)^2}{(-4)^2-4} = \frac{9-16}{16-4} = \frac{-7}{12}$

⇒ f (x) < 0 for x ∈ (-∞ ,-3)

b. (-3, -2)

put k = -2.5 from the given interval

We get $f(-2.5)= \frac{9-(-2.5)^2}{(-2.5)^2-4} = \frac{9-6.25}{6.25-4} = \frac{2.75}{2.25} > 0$

⇒ f (x) > 0 for x ∈ (-3,-2)

c. (-2, 2)

put k = 0 from the given interval

We get $f(0)= \frac{9-(0)^2}{(0)^2-4} = \frac{9}{-4} = -\frac{9}{4} < 0$

⇒ f (x) < 0 for x ∈ (-2,2)

d. (2, 3)

put k =2.5 from the given interval

We get $f(2.5)= \frac{9-(2.5)^2}{(2.5)^2-4} = \frac{9-6.25}{6.25-4} = \frac{2.75}{2.25} > 0$

⇒ f (x) > 0 for x ∈ (2,3)

e. (infinity, 3)

put k = 4 from the given interval

We get $f(4)= \frac{9-(4)^2}{(4)^2-4} = \frac{9-16}{16-4} = \frac{-7}{12}$

⇒ f (x) < 0 for x ∈ (3,∞)

7 0

3 years ago

Choose the fraction below that would make the following proportion true. 3/4 = ?/? A 1/2 B 4/5 C 6/8 or D 9/10

Daniel [21]

Answer:

Step-by-step explanation:

3/4 x 2/2= 6/8

6/8 = 6/8

5 0

3 years ago