Answer:
-4
Step-by-step explanation:
If anything the first thing you would want to do is covert your fraction so a decimal. (-4 1/2) as a decimal is -4.50. From there it would be easier to divide. to get an answer of -4
Answer: 16517 dollars
Step-by-step explanation:
Given that x is the number of years after 2000.
In 2005, the number of years x = 4
Because the equation was modelled for 4 year college courses
The best estimate for the average cost of tuition in 2005 will be
ŷ = 937.98(4) + 12,764.90
Y = 3751.92 + 12764.9
Y = 16516.82 dollars
Y = 16517 dollars
Answer:
The lines are parallel.
Step-by-step explanation:
Given the lines
Writing the equations in the slope-intercept form
where m is the slope and b is the y-intercept
Thus, the slope = m₁ = -2/3
also
Thus, the slope = m₂ = -2/3
- We know that parallel lines have equal slopes
As
m₁ = m₂
Thus, the lines are parallel.
Let s be the side length of the square. The dimensions of the rectangle are three times the side of the square (i.e. 3s), and two less than the side of the square (i.e. s-2).
So, the area of this rectangle is
The area of the square is 
, and we know that the two areas are the same, so we have
The solution s=0 would lead to the extreme case where the rectangle and the square are actually a point, so we accept the solution s=3.
Answer:
a. 2.28%
b. 30.85%
c. 628.16
d. 474.67
Step-by-step explanation:
For a given value x, the related z-score is computed as z = (x-500)/100.
a. The z-score related to 700 is (700-500)/100 = 2, and P(Z > 2) = 0.0228 (2.28%)
b. The z-score related to 550 is (550-500)/100 = 0.5, and P(Z > 0.5) = 0.3085 (30.85%)
c. We are looking for a value b such that P(Z > b) = 0.1, i.e., b is the 90th quantile of the standard normal distribution, so, b = 1.281552. Therefore, P((X-500)/100 > 1.281552) = 0.1, equivalently P(X > 500 + 100(1.281552)) = 0.1 and the minimun SAT score needed to be in the highest 10% of the population is 628.1552
d. We are looking for a value c such that P(Z > c) = 0.6, i.e., c is the 40th quantile of the standard normal distribution, so, c = -0.2533471. Therefore, P((X-500)/100 > -0.2533471) = 0.6, equivalently P(X > 500 + 100(-0.2533471)), and the minimun SAT score needed to be accepted is 474.6653
