Subtract 3 from both sides so that the equation becomes -2x^2 + 5x - 13 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -5 ± √((5)^2 - 4(-2)(-13)) ] / ( 2(-2) )
x = [-5 ± √(25 - (104) ) ] / ( -4 )
x = [-5 ± √(-79) ] / ( -4)
Since √-79 is nonreal, the answer to this question is that there are no real solutions.
It would be the answer with Juana. Additive integers are adding a postive and negative number to add to zero ex) -5+5=0. So in this situation you can think of west and east as positive and negative.
Answer:
They are hard and you Just have to follow the steps of solbing them
Step-by-step explanation:
Answer:
No Solution
Step-by-step explanation:
-3x+6=-3x-5
+5 +5
-3x+11=-3x
+3 +3
11=0
No Solution
Answer:
( x - 2 )^2 + ( y - 1 )^2 = 1
Step-by-step explanation:
As i previously explained,
The general form of equation for a circle is ( x - h )^2 + ( y - k )^2 = r^2.
h and k are the co-ordinates of the center of circle and r is the radius
Here, We have (2,1) as the co-ordinates of the center of circle
Now,
( x - h )^2 + ( y - k )^2 = r^2
or,( x - 2 )^2 + ( y - 1 )^2 = r^2
The radius of the circle is 1 units(from figure)
So, put that in, we get
( x - 2 )^2 + ( y - 1 )^2 = 1^2
or, ( x - 2 )^2 + ( y - 1 )^2 = 1
You can simplify this or leave it here.