There is a horizontal asymptote at y = 0 so the range is y < 0
Answer:
x=0
y=6
Step-by-step explanation:
3y- 12x = 18
2y-8x= 12
rearrange the equation
2y-8x=12
add 8x to both sides
2y=8x+12
divide both sides by 2
y=4x+6
now substitute it into 3y-12x=18
3(4x+6)-12x=18
simplify
12x+18-12x=18
simplify
18=18
x=0
substitute to find y
2y-8(0)=12
2y=12
y=6
Recheck:
3(6)-12(0)=18
18=18
2(6)-8(0)=12
12=12
30:42 is represented as 30/42
The lowest form for that is 5/7. Hope that helped. Good luck
First divide by 3 because we don't want any factor in front of the x² when doing factorization:
3x² + 15x – 18 = 0 => x² + 5 - 6 = 0
Then find the two numbers that multiply to -6 and add up to +5:
x² + 5 - 6 = 0 => (x-1)(x+6) = 0
So the solutions are x=1 or x=-6, that's answer B.