The <em>simple annual interest</em> rate for the $ 525 loan is equal to 46.35 %.
<h3>What is the interest rate behind a pay back?</h3>
In this situation we assume that the loan does not accumulate interests continuously in time. Hence, the <em>interest</em> rate for paying the loan back 75 days later is:
575 = 525 · (1 + r/100)
50 = 525 · r /100
5000 = 525 · r
r = 9.524
The loan has an <em>interest</em> rate of 9.524 % for 75 days. <em>Simple annual interest</em> rate is determine by rule of three:
r' = 9.524 × 365/75
r' = 46.350
The <em>simple annual interest</em> rate for the $ 525 loan is equal to 46.35 %.
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Answer:
The value of x for the given expression is (95/27)
Step-by-step explanation:
Here, the given expression is:

Now here solving for the value of x , we get

Now, taking the variable terms on 1 side, we get

or, 
Hence, the value of x = (95/27)
Answer:
452.39 would be the volume
Step-by-step explanation:
V = π r² h
3.14 x 9 x 16
It is D, because you have to get the denomenator"s equal so 9 times 4 is 36 and you take the numerator's and times by the other's denominator then subtract them to get 5/36
<em>Find Slope:</em>
y = -x + 3
slope = -1
Perpendicular slope = 1
<em>Sub Slope into Equation </em>
y = mx + c
Found that m = 1 (slope = 1)
y = x + c
<em>Find C</em>
At (-1,3)
3 = (-1) + c
c = 3 + 1
c = 4
<em>Sub C into the equation </em>
y = x + 4