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Serga [27]
3 years ago
9

Consider a multiple-choice question exam consisting of 20 questions. Assume that each question has four possible choices, and on

ly one of them is correct. If a student is going to guess solutions at the exam, what is the probability that he answers at most three of them are correct
Mathematics
1 answer:
elena-s [515]3 years ago
8 0

Answer:

0.22514

Step-by-step explanation:

Given :

1 answer from 4 options

p = 1/4 = 0.25 ; q = 1 - 0.25 = 0.75

n = 20

P(x ≤ 3) = p(x =0) +p(x=1) + p(x=2) +p(x=3)

P(x = x) = nCr * p^x * q^(n-r)

p(x =0) = 20C0 * 0.25^0 * 0.75^20 = 0.00317

p(x =1) = 20C1 * 0.25^1 * 0.75^19 = 0.02114

p(x =2) = 20C2 * 0.25^2 * 0.75^18 = 0.06694

p(x =3) = 20C3 * 0.25^3 * 0.75^17 = 0.13389

P(x ≤ 3) = 0.00317+0.02114+0.06694+0.13389 = 0.22514

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Answer: UV = 52

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Additive property of length, or the segment addition postulate, states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

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<u>Given information</u>

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<u />

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UV = 2x + 14 = 2 (19) + 14 = \boxed{52}

Hope this helps!! :)

Please let me know if you have any questions

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