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sergeinik [125]
3 years ago
7

Write the equation of the line that is parallel to the line y= 3x+ 6 and passes through the point (4, 7).

Mathematics
2 answers:
Olenka [21]3 years ago
7 0

Answer:

Is this slope?

Step-by-step explanation:

GREYUIT [131]3 years ago
6 0

Answer:

y = 3x - 5

Step-by-step explanation:

Let the equation be y = mx + c

Since the equation is parallel to y = 3x + 6, gradients of the two eqns are the same

therefore, m = 3

sub (4, 7):

7 = 3(4) + c

c = -5

therefore, equation of the line is y = 3x - 5

You might be interested in
In an arithmetic sequence, t4 + t5 + t6 = 300, and t15 +t16+ t17 = 201. Find t18.
stiks02 [169]
In an arithmetic sequence:
Tn=t₁+(n-1)d

t₄=t₁+(4-1)d=t₁+3d
t₅=t₁+(5-1)d=t₁+4d
t₆=t₁+(6-1)d=t₁+5d

t₄+t₅+t₆=(t₁+3d) +(t₁+4d)+(t₁+5d)=3t₁+12d

Therefore:
3t₁+12d=300    (1)


t₁₅=t₁+(15-1)d=t₁+14d
t₁₆=t₁+(16-1)d=t₁+15d
t₁₇=t₁+(17-1)d=t₁+16d

t₁₅+t₁₆+t₁₇=(t₁+14d)+(t₁+15d)+(t₁+16d)=3t₁+45d

Therefore:
3t₁+45d=201    (2)

With the equations (1) and (2) we make an system of equations:

3t₁+12d=300
3t₁+45d=201

we can solve this system of equations by reduction method.

  3t₁+12d=300
-(3t₁+45d=201)
-----------------------------
       -33d=99      ⇒d=99/-33=-3

3t₁+12d=300
3t₁+12(-3)=300
3t₁-36=300
3t₁=300+36
3t₁=336
t₁=336/3
t₁=112

Threfore:

Tn=112+(n-1)(-3)
Tn=112-3n+3
Tn=115-3n

Now, we calculate T₁₈:

T₁₈=115-3(18)=115-54=61

Answer: T₁₈=61




5 0
3 years ago
Help me please I dont get this
inessss [21]

Answer/Step-by-step explanation:

Area of a rectangle = Length × Width

Width of the large rectangle = a

Length of the large rectangle = (2 + 3 + 4)

Therefore:

Area of the large rectangle = a(2 + 3 + 4)

6 0
3 years ago
GIVING BRAINLIEST PLEASE HELP
Murljashka [212]

Answer:

I think it is 2/ 15 pls mark as breanliest

3 0
3 years ago
HELP! IS THIS RIGHT?
svlad2 [7]

Yes, this is the right answer

4 0
3 years ago
Read 2 more answers
F(x) = (x + 2) (x - 7)3
mote1985 [20]

Answer:

y=3x^2 -15x-42

Step-by-step explanation:

8 0
3 years ago
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