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luda_lava [24]
3 years ago
8

Pls help ASAP ‼️ will give brainliest

Mathematics
1 answer:
Tcecarenko [31]3 years ago
8 0

Answer:

356.53

Step-by-step explanation:

Calculate the semicircle and square areas separately. For the semicircle, A = πr²/2, so 100.53

And for the square, A = a², so 256

Hope this helps

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* Is a Binomial

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* Not a Binomial because probability of success is not constant

c) Evelyn has a 75% chance of getting an A in each class she takes. Let X be the number of times Evelyn earns an A during four years at SJSU.

* Is a Binomial

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7 0
3 years ago
The number is three digits, the number is even, the tens digit is half the hundreds digit, the sum of the digit is 14 what is th
ser-zykov [4K]

Let x represent the digit in the hundreds place, y represent the digit in the tens place, and z represent the digit in the ones place. What do we know about each digit?

x: twice y (2, 4, 6, or 8)

y: half of x (1, 2, 3, or 4)

z: an even number (0, 2, 4, 6, or 8).

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Choose one of the digits and look at your options (if any).

when x=2, then y = 1, which means z has to be 11 (NOT VALID)

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For fun, let's see if any other numbers work:

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5 0
3 years ago
Ruth Behr has ¾ liters of soda in her refrigerator. She poured 1/8 liter of soda in multiple cups. Enter the number of cups Ruth
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Answer:

6

Step-by-step explanation:

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3 0
3 years ago
Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam
Vlad [161]

Answer

P(A) = 0.30

P(B) = 0.77

P(A\ n\ B) = 0.22

P(A\ u\ B) = 0.85

Explanation:

Given

See attachment for proper data presentation

n = 100 --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

Here:

Yes = 22 and No = 8

n(A) = Yes + No

n(A) = 22 + 8

n(A) = 30

P(A) is then calculated as:

P(A) = \frac{n(A)}{Sample}

P(A) = \frac{30}{100}

P(A) = 0.30

Solving (b): P(B)

We only consider data in the Yes column.

Here:

(1) = 22    (2) = 25 and (3) = 30

n(B) = (1) + (2) + (3)

n(B) = 22 + 25 + 30

n(B) = 77

P(B) is then calculated as:

P(B) = \frac{n(B)}{Sample}

P(B) = \frac{77}{100}

P(B) = 0.77

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

i.e. [Supplier 1][Yes]

This is represented as: n(A n B)

n(A\ n\ B) = 22

The probability is then calculated as:

P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}

P(A\ n\ B) = \frac{22}{100}

P(A\ n\ B) = 0.22

Solving (d): P(A u B)

This is calculated as:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)

This gives:

P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}

Take LCM

P(A\ u\ B) = \frac{30+77-22}{100}

P(A\ u\ B) = \frac{85}{100}

P(A\ u\ B) = 0.85

7 0
3 years ago
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