Answer:
90(Initial Weight) + <em>W*t = 138 Kg </em>
So the Weight increased per month is 6Kg
Explanation:
The Wrestler started at 90Kg weight
After 8 months, Wrestler had a weight of 138Kg.
The weight gained by the wrestler in '<em>t'</em> months is:
138(Kg) - 90 (Kg) = 48 (Kg)
From above equation we can see that a difference of 48Kg was attained by Wrestler.
Since the question stated that, the weight increased at a constant rate, so we can calculate the weight gained each month over a period of 8 months.
Weight gained per month: 48 (Kg) / 8 (Months) = 6 (Kg) / (Month)
So now we can write the equation in terms of <em>W</em>(Gained per month) and<em> t</em>( t number months)
The equation becomes:
90Kg (Initial Weight) + <em>W.t = 138 Kg </em>
<em>( where 'W' is Weight increased per month and 't' is number of months passed)</em>
A: Name at least two indicators that a driver must not turn right at this intersection these are Indicator lighting are amber in color and may be positioned on the front, the rear and every so often on the aspect of the automobile on each the left and proper-hand sides.
<h3>When the 2 roads intersect on the site visitors mild flip proper?</h3>
If each car are turning properly then they do not want to move every other's paths. When you return back to an intersection and the street past is full of cars going withinside the identical route you have to wait till there's room to absolutely move the intersection, even in case your site visitors mild turns green.
Indicator lighting are amber in color and may be positioned on the front, the rear and every so often on the aspect of the automobile on each the left and proper-hand sides. You use your signs to expose an meant extrude of the route, whether or not turning left or proper or transferring out into site visitors.
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The moment of inertia for rotation about the perpendicular axis through the edge of the disk is 3.78 × 10⁻⁵ kgm².
<h3>
Moment of inertia</h3>
Moment of inertia is referred to as the product of mass of section and the square of the distance between the reference axis and the centroid of the section.
Moment of inertia of solid cylinder or disk is expressed as;
I = 1/2 × mr²
Given the data in the question;
- Mass of disk m = 21g = 0.021kg
- Diameter of disk d = 12cm = 0.12m
- Radius r = d/2 = 0.12m / 2 = 0.06m
We substitute our given value into the expression above.
I = 1/2 × 0.021kg × (0.06m)²
I = 1/2 × 0.021kg × 0.0036m²
I = 3.78 × 10⁻⁵ kgm²
Therefore, the moment of inertia for rotation about the perpendicular axis through the edge of the disk is 3.78 × 10⁻⁵ kgm².
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Answer:
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