Answer:
Inverse Laplace of 
will be 
Step-by-step explanation:
We have to find the inverse Laplace transform of 
We know that of 
is 
As in H(s) there is square of 
So i inverse Laplace there will be multiplication of t
So the inverse Laplace of 
will be
Answer:
if it is put into a equation this would be it
2(x^2+6x+9) - (1.57)(x^2+6x+9)
Step-by-step explanation:
(x+3)(2x+6) - 1/2(3.14)(x+3)(x+3)
(2x^2+6x+6x+18) - 1/2(3.14)(x^2+3x+3x+9)
(2x^2+12x+18) - 1/2(3.14)(x^2+6x+9)
2(x^2+6x+9) - (1.57)(x^2+6x+9)
2(x^2+6x+9) is the rectangle at the bottom
(1.57)(x^2+6x+9) is the semicircle that is taking out of the shaded area
2x+40=60
2x=20
x=10
Answer:10
Thus, the final answers are 1 and -1/8.
