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Elina [12.6K]
3 years ago
13

A line passes through the points (-1,10) and (3,2). Which shows the graph of this line?

Mathematics
1 answer:
GuDViN [60]3 years ago
5 0
It’s the 4th graph:)
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How much money will be in Account A at the end of 3 years? $ How much money will be in Account B at the end of 3 years? $.
nalin [4]

Account A is having $1,093 after 3 years. and Account B is having $1,120 after 3 years.

<h3>What is compound interest?</h3>

Compound interest is the interest on a loan or deposit calculated based on the initial principal and the accumulated interest from the previous period.

Elisa put $1,000 in each bank.

Account A: gives her at a rate of 3% per annum compounded annually.

Account B: $40 bonus is added to the account each year.

After 3 years, account A will have

\rm Account \ A = 1000(1.03)^3\\\\Account \ A = 1093

Account A is having $1,093 after 3 years.

After 3 years, account B will have

\rm Account \ B= 1000 + 3(40)\\\\Account \ B= 1,120

Account B is having $1,120 after 3 years.

More about the compound interest link is given below.

brainly.com/question/25857212

3 0
2 years ago
Some help me please :( I really need help with this
katrin2010 [14]
First part, in quadrilateral WXYZ, WX is parallel to ZY because both sides are equal while the other parallel segments WZ and XY are equal but different side lengths.

The measure of angle Z is 78 because both of the pictures are the same, only rotated. and angle S and Z are acute.
7 0
3 years ago
I need to know how to do the whole thing and understand it.
patriot [66]

We are given the data on the number of candies handed by neighborhood A and neighborhood B.

Let us first find the mean and variance of each neighborhood.

Mean:

\bar{x}_A=\frac{\sum x}{N_1}=\frac{12}{6}=2\bar{x}_B=\frac{\sum x}{N_2}=\frac{20}{6}=3.33

Variance:

s_A^2=\frac{\sum x^2}{N_1}-\bar{x}_A^2=\frac{28}{6}-2^2=0.667s_B^2=\frac{\sum x^2}{N_2}-\bar{x}_B^2=\frac{80}{6}-3.33^2=2.244

A. Null hypothesis:

The null hypothesis is that there is no difference in the mean number of candies handed out by neighborhoods A and B.

H_0:\;\mu_A=\mu_B

Research hypothesis:

The research hypothesis is that the mean number of candies handed out by neighborhood A is more than neighborhood B.

H_a:\;\mu_A>\mu_B

Test statistic (t):

The test statistic of a two-sample t-test is given by

t=\frac{\bar{x}_A-\bar{x}_B}{s_p}

Where sp is the pooled standard deviation given by

\begin{gathered} s_p=\sqrt{\frac{N_1s_1^2+N_2s_2^2}{N_1+N_2-2}(\frac{N_1+N_2}{N_1\cdot N_2}}) \\ s_p=\sqrt{\frac{6\cdot0.667+6\cdot2.244}{6+6-2}(\frac{6+6}{6\cdot6})} \\ s_p=0.763 \end{gathered}t=\frac{2-3.33}{0.763}=-1.74

So, the test statistic is -1.74

Critical t:

Degree of freedom = N1 + N2 - 2 = 6+6-2 = 10

Level of significance = 0.05

The right-tailed critical value for α = 0.05 and df = 10 is found to be 1.81

Critical t = 1.81

We will reject the null hypothesis because the calculated t-value is less than the critical value.

Interpretation:

This means that we do not have enough evidence to conclude that neighborhood A gives out more candies than neighborhood B.

6 0
1 year ago
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