Make sure you post the picture of the tree, so I can answer.
Answer:
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Explanation:
Ribosomal RNA<span> (</span>rRNA<span>) associates with a set of </span>proteins<span> to form ribosomes. These complex structures, which physically move along an </span>mRNA<span> molecule, catalyze the assembly of amino acids into </span>protein<span> chains. They also bind </span>tRNAs<span> and various accessory molecules necessary for </span>protein<span> synthesis
</span>The Three Roles of RNA in Protein Synthesis - Molecular Cell Biology ...<span>https://www.ncbi.nlm.nih.gov/books/NBK21603/</span>
Answer:
3/4
Explanation:
If we assume simple dominance and independent assortment for each trait, we can use Mendel's Law of Segregation to predict the phenotypic proportions in the offspring of the parental cross AABBCc x AabbCc.
<h3><u>Gene A</u></h3>
AA x Aa
- F1 genotypes: 1/2 AA, 1/2 Aa
- F1 phenotypes: all A
<h3 /><h3><u>Gene B</u></h3>
BB x bb
- F1 genotypes: 1 Bb
- F1 phenotypes: all B
<h3 /><h3><u>Gene C</u></h3>
Cc x Cc
- F1 genotypes: 1/4 CC, 2/4 Cc, 1/4 cc
- F1 phenotypes: 3/4 C, 1/4 cc
We want to know the proportion of progeny with all dominant phenotype (A_B_C_). Since the genes are independent, we can multiply the probabilities of each gene to obtain the overall probability of having a ABC progeny:
<h3>1 A_ x 1 B_ x 3/4 C_ = 3/4 A_B_C_</h3>