Answer:
-9/7 for the first, 0 for the second the third doesn't exist so also 0 5/3 for the final one
1. first parabola is up, so a are going to be positive
y = a(x-r)(x-s),
roots -7,-3, so we can write y=a(x+7)(x+3) [1]
we can take point (-5,-2), substitute into equation [1], and find value of a
-2=a(-5+7)(-5+3)
-2=a*2*(-2)
a=1/2
so first parabola has an equation
y=1/2(x+7)(x+3)
2. second parabola
y=a(x-r)(x-s) roots are 2 and 4 so we ca write
y=a(x-2)(x-4) take point (3,4) and substitute into this equation
4 =a(3-2)(3-4)
4=-a
a=-4, and it will look down
y=-4(x-2)(x-4)
Answer:
There are 6 equilateral triangles
you get an isosceles triangle
the height of the equilateral triangle is 4
this is all I have so far :)
