Which of the following high speed trains are traveling at a rate of 150 miles per hour? A: a train that travels 100 miles in 2/3
1 answer:
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The image of this question is missing and so i have attached it.
Answer:
dd/dt = 4.47 ft/s
Step-by-step explanation:
From the image attached, let's denote the following;
d = horizontal distance beneath pulley
h = height of pulley
l = diagonal from the pulley to the head of the person
v = velocity of rope rising
Using pythagoras theorem;
l² = d² + h²
Differentiating with respect to time and considering h = c^(te) gives;
2l(dl/dt) = 2d(dd/dt)
We are given;
d = 20 ft
h = 10 ft
v = 4 ft/s
We know that velocity in this case is change in diagonal distance with time. Thus;
v = dl/dt = 4 ft/s
From earlier, we saw that;
2l(dl/dt) = 2d(dd/dt)
Thus, reducing it gives
(dl/dt)(l/d) = dd/dt
Now, l² = d² + h²
l = √(d² + h²)
Also, v = dl/dt = 4
Thus;
4(√(d² + h²))/d = dd/dt
4(√(20² + 10²))/20 = dd/dt
dd/dt = 4.47 ft/s
Answer:
We conclude that:
∠A = ∠ FEC
Step-by-step explanation:
Given
△ABD ≅ △EFC
To determine:
∠A =
As
△ABD ≅ △EFC
So the triangles △ABD and △EFC are congruent to each other.
- We know that congruent triangles have equal corresponding parts.
Please check the attached graph.
From the graph, it is clear that ∠A is correspondent to ∠E.
∠A = ∠E
From the attached figure, it is clear that:
∠F can also be denoted by ∠ FEC
as
∠A = ∠E
so
∠A = ∠ FEC
Therefore, we conclude that:
∠A = ∠ FEC
