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Alex_Xolod [135]
2 years ago
8

On a floor plan for Roscdale Middde School, 1l inch

Mathematics
1 answer:
Rashid [163]2 years ago
6 0

Answer:

The answer is A) 20 feet by 30 feet

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Centimeters and meters size of window
Gnom [1K]

Answer:

Tiff, hon, just measure a window, your wasting your time

Step-by-step explanation:

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Which BEST describes the association between goals by the Red Team and the Blue Team?
Andru [333]
B positive association
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Jessie estimated the weight of his cat to be 12 pounds. The actual weight of the cat is 15 pounds.
Juliette [100K]

Answer:

The correct answer is 20%

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5 0
3 years ago
Read 2 more answers
Make up this problem yourself 3 divided by 1/2
Helen [10]

Answer:

3 : (1/2) =\frac{6}{1} =6

Step-by-step explanation:

Divide: 3 : \frac{1}{2} =\frac{3}{1} *\frac{2}{1} =\frac{3 * 2}{1*1} =\frac{6}{1} =6

Dividing two fractions is the same as multiplying the first fraction by the reciprocal value of the second fraction. The first sub-step is to find the reciprocal (reverse the numerator and denominator, reciprocal of \frac{1}{2} is \frac{2}{1}) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators.

In words - three divided by one half = six.

8 0
2 years ago
Two ships leave a harbor together, traveling on courses that have an angle of 135°40' between them. If they each travel 402 mile
mario62 [17]

Answer:

Therefore they are 734.106 miles apart.

Step-by-step explanation:

Given that ,

Two ships have a harbor together. The angle between two ships  is  135°40'. Each of two ships travel 402 miles.

It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.

Let ∠B= 135°40', and AB = 402 miles , BC =  402 miles

Then the distance between the ships = AC

We know

The sum of all angles = 180°

⇒∠A+∠B+∠C=180°

⇒∠A+135°40'+∠C=180°

⇒2∠A= 180°- 135°40'      [ since ∠A=∠C]

⇒2∠A=44°60'

⇒∠A= 22°30'

Again we know that,

\frac{AB}{sin\angle C}=\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Taking last two ratio,

\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Putting the value of BC , AC ,∠A,∠B

\frac{402}{sin 22^\circ30'}=\frac{AC}{sin 135^\circ40'}

\Rightarrow AC=\frac{402 \times sin135^\circ40'}{sin 22^\circ30'}

         ≈734.106 miles

Therefore they are 734.106 miles apart.

3 0
3 years ago
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