1/3 log 125 can be rewritten as (1/3) log 5^3 = log 5
Similarly, 1/3 log 8 can be re-written as 1/3 log 2^3, same as (1/3)(3 log 2)= log 2
Thus, the fraction can be written in simpified form as log 5 / log 2.
The second term is the same as log m^5.
Thus, your final result is (log 5) / (log 2) + log m^5.
here you go
instead of giving you a link like that other person, here are some actual screenshots instead, youre welcome ;D
Answer:
Step-by-step explanation:
Since n < 30, we will find the t-score and compare that to the t-score of a significance level of 1%.
Since they are asking if the difference is significant, we will have a two tailed test, with degree of freedom being 22, so our critical values are
t < -2.704 and t > 2.704
Our t-value for this situation is
t = ([µ + 5.8] - µ)/(1.4/√23)
It's µ + 5.8 because the problem told us that their levels are 5.8 mm higher than the average, so it's the average, plus 5.8
Simplify the equation...
t = 5.8/(1.4/√23)
t = 19.868
19.868 > 2.704, the evidence supports that there is significant difference between the sample and the population
Answer:
Equation: 2.35x+5.50=89.50
ANSWER FOR A.) 95.8
Step-by-step explanation:
A.) 2.35×8=18.8
5.50×14=77
18.8×77=95.8
Hope this Helps with your Math Problem :D
