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sertanlavr [38]
3 years ago
6

IF THE ORIGINAL POINT IS (6,15) AND THE SCALE FACTOR IS 1/3,WHAT IS THE NEW POINT

Mathematics
1 answer:
AysviL [449]3 years ago
8 0
I believe it would be (9, 16). My reasoning for this is that if the slope is 1/3, then x would increase by 3 and y would increase by 1.
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2 4/10 + 3 5/8 = what does it equal
photoshop1234 [79]
2 4/10 + 3 5/8
= 6 1/40
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Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

f'(y)=0\implies f(y)=C

\implies F(x,y)=x^2y^3+\ln(x+y^2)=C

With y(1)=2, we have

8+\ln9=C

so

\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}

8 0
3 years ago
3/12 ÷ 6/12 ????????????
Ahat [919]

Answer:

The answer is 0.5, or 1/2.

3/12 ÷ 6/12 = 1/2

Hope this helps!


4 0
3 years ago
What is the slope of the line whose equation is -3x y=12?
stepan [7]
-3x+y=12
y=3x + 12
slope=3
8 0
3 years ago
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