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Elena L [17]
2 years ago
15

Simplified expression of 7z + 8 + 5z – 5z – 9?

Mathematics
1 answer:
Likurg_2 [28]2 years ago
6 0

Answer:

7z-1 hope this helps

Step-by-step explanation:

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An airline experiences a no-show rate of 6%. What is the maximum number of reservations that it could accept for a flight with a
LekaFEV [45]

Let Xb be the number of reservations that are accommodated. Xb has the binomial distribution with n trials and success probability p = 0.94

In general, if X has the binomial distribution with n trials and a success probability of p then
P[Xb = x] = n!/(x!(n-x)!) * p^x * (1-p)^(n-x)
for values of x = 0, 1, 2, ..., n
P[Xb = x] = 0 for any other value of x.

To use the normal approximation to the binomial you must first validate that you have more than 10 expected successes and 10 expected failures. In other words, you need to have n * p > 10 and n * (1-p) > 10.

Some authors will say you only need 5 expected successes and 5 expected failures to use this approximation. If you are working towards the center of the distribution then this condition should be sufficient. However, the approximations in the tails of the distribution will be weaker espeically if the success probability is low or high. Using 10 expected successes and 10 expected failures is a more conservative approach but will allow for better approximations especially when p is small or p is large.

If Xb ~ Binomial(n, p) then we can approximate probabilities using the normal distribution where Xn is normal with mean μ = n * p, variance σ² = n * p * (1-p), and standard deviation σ

I have noted two different notations for the Normal distribution, one using the variance and one using the standard deviation. In most textbooks and in most of the literature, the parameters used to denote the Normal distribution are the mean and the variance. In most software programs, the standard notation is to use the mean and the standard deviation.

The probabilities are approximated using a continuity correction. We need to use a continuity correction because we are estimating discrete probabilities with a continuous distribution. The best way to make sure you use the correct continuity correction is to draw out a small histogram of the binomial distribution and shade in the values you need. The continuity correction accounts for the area of the boxes that would be missing or would be extra under the normal curve.

P( Xb < x) ≈ P( Xn < (x - 0.5) )
P( Xb > x) ≈ P( Xn > (x + 0.5) )
P( Xb ≤ x) ≈ P( Xn ≤ (x + 0.5) )
P( Xb ≥ x) ≈ P( Xn ≥ (x - 0.5) )
P( Xb = x) ≈ P( (x - 0.5) < Xn < (x + 0.5) )
P( a ≤ Xb ≤ b ) ≈ P( (a - 0.5) < Xn < (b + 0.5) )
P( a ≤ Xb < b ) ≈ P( (a - 0.5) < Xn < (b - 0.5) )
P( a < Xb ≤ b ) ≈ P( (a + 0.5) < Xn < (b + 0.5) )
P( a < Xb < b ) ≈ P( (a + 0.5) < Xn < (b - 0.5) )

In the work that follows X has the binomial distribution, Xn has the normal distribution and Z has the standard normal distribution.

Remember that for any normal random variable Xn, you can transform it into standard units via: Z = (Xn - μ ) / σ

In this question Xn ~ Normal(μ = 0.94 , σ = sqrt(0.94 * n * 0.06) )

Find n such that:

P(Xb ≤ 160) ≥ 0.95

approximate using the Normal distribution
P(Xn ≤ 160.5) ≥ 0.95

P( Z ≤ (160.5 - 0.94 * n) / sqrt(0.94 * n * 0.06)) ≥ 0.95

P( Z < 1.96 ) ≥ 0.95

so solve this equation for n

(160.5 - 0.94 * n) / sqrt(0.94 * n * 0.06) = 1.96

n = 164.396

n must be integer valued so take the ceiling and you have:

n = 165.

The air line can sell 165 tickets for the flight and accommodate all reservates at least 95% of the time

If you can understand that...

7 0
3 years ago
Which of the following is the equation for the graph shown?
Allushta [10]
It would probably be the second option.

3 0
3 years ago
A. equals 2<br><br> B. does not exist<br><br> C. equals 0<br><br> D. equals 1
insens350 [35]

The limit of f(x) as x goes to 2 is given by:

C. 0.

<h3>What is a limit?</h3>

A limit is given by the value of function f(x) as x tends to a value a, that is, we have to look to the left of x = a and to the right of x = a, and if these values are equal, this is the limit of the function.

In this problem, we have that:

  • To the left of x = 2, f(x) approaches 0.
  • To the right of x = 2, f(x) approaches 0.

Since the lateral limits are equal, the limit of the function as x approaches 2 is of 0 and option C is correct.

More can be learned about limits at brainly.com/question/26270080

#SPJ1

6 0
2 years ago
Given the following matrices A and B, find an invertible matrix U such that UA = B:
Naddik [55]

<span>A and B must be invertible, we have UA=B, since A is invertible.  A^-1 exists, by multiplying with A^-1, we have UA A^-1 =B A^-1. But AA^-1 = I (identity matrix) and XI=X, for all matrix X, we find UI= B A^-1, and U= B A^-1.</span>

3 0
3 years ago
HELPPPPPpppppppkdjrjr
Daniel [21]
I think the answer might be C i hope this helps you
8 0
3 years ago
Read 2 more answers
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