Answer:
= A1 * (A2 + A3)
Explanation:
In order to calculate the total weight of the equipment, he would need to first add the total weight of each item. This is done by adding the weight of the item by the weight of the packaging. Once you have this amount you can multiply this value by the total number of items being shipped and that should give you the total weight of the shipment. Using the cells, this can be calculated with the following formula in Excel...
= A1 * (A2 + A3)
The most commonly accepted amount of colors on one slide is 4
Answer:
a)
#include <iostream>
using namespace std;
int main() {
bool a,b,c;
cin>>a>>b;
if(a^b)//X-OR operator in C++.
c=true;
else
c=false;
cout<<c;
return 0;
}
b)
#include <iostream>
using namespace std;
int main() {
bool a,b,c,d;
cin>>a>>b>>c;
if((a^b)^c)//X-OR operator in C++.
d=true;
else
d=false;
cout<<d;
return 0;
}
Explanation:
The above written programs are in C++.There is an operator (^) called X-OR operator in C++.It returns true if the number of 1's are odd and returns false if the number of 1's are even.
In the if statement I have user X-OR operator(^) to find the result and storing the result in another boolean variable in both the questions.
Answer:
data, sort and filter, text filters
Explanation:
ed 2020
Answer:
This is not true
Explanation:
The optimal Huffman code is used to encrypt and compress text files. It uses fixed-length code or variable-length code for encryption and compression of data.
The professor's character code is similar to Huffman's variable-length coding which uses variable length od binary digits to represent the word strings. The file size of the text file above is;
= 6 x 1 + 2 x 2 + 3 x 2 + 2 x 2 + 8 x 1 = 28 bits
This would be the same for both cases.
The encrypt would be the problem as the encoded and decoding of the characters B and E may cause an error.
