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frozen [14]
3 years ago
13

Umm like can someone help me pls I need this answered ASAP thx

Mathematics
2 answers:
grigory [225]3 years ago
7 0

Answer: sorry mate. im as stuck as you are

Step-by-step explanation:

Ostrovityanka [42]3 years ago
6 0
To find the x-intercept, substitute in
0
0
for
y
y
and solve for
x
x
. To find the y-intercept, substitute in
0
0
for
x
x
and solve for
y
y
.
x-intercept(s):
(
5
,
0
)
(
5
,
0
)
y-intercept(s):
(
0
,
−
15
)
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ella [17]
11.
-8y=24

We want to isolate y to get the value of 1y. Divide both sides by -8
y= -3

Final answer: y=-3

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This is the associative property of addition (D).
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Find the missing angle and classify the triangle below.
sergij07 [2.7K]

Answer:

Hello! answer: 60 and the triangle is a Equilateral because each measure is the same HOPE THAT HELPS!

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A rectangular box is to have a square base and a volume of 20 ft3. If the material for the base costs $0.35 per square foot, the
denpristay [2]

Answer:

Length = 2 ft

Width = 2 ft

Height = 5 ft

Step-by-step explanation:

Let the square base of the box has one side = x ft

Therefore, area of the base = x² ft²

Cost of the material to prepare the base = $0.35 per square feet

Cost to prepare the base = $0.35x²

Let the height of the box = y ft

Then the volume of the box = x²y ft³ = 20

y=\frac{20}{x^{3} } -----(1)

Cost of the material for the sides = $0.10 per square feet

Area of the sides = 4xy

Cost to prepare the sides of the box = $0.10 × 4xy

                                                             = $0.40xy

Cost of the material to prepare the top = $0.15 per square feet

Cost to prepare the top = $0.15x²

Total cost of the box = 0.35x² + 0.40xy + 0.15x²

From equation (1),

Total cost C=0.35x^{2}+(0.40x)\times \frac{20}{x^{2} }+0.15x^{2}

C=0.35x^{2}+\frac{8}{x}+0.15x^{2}

C=0.5x^{2}+\frac{8}{x}

Now we take the derivative of C with respect to x and equate it to zero,

C'=0.5(2x)-\frac{8}{x^{2}} = 0

x-\frac{8}{x^{2}}=0

x=\frac{8}{x^{2} }

x^{3}=8

x = 2 ft.

From equation (1),

(2)^{2}y=20

4y = 20

y = 5 ft

Therefore, Length and width of the box should be 2 ft and height of the box should be 5 ft for the minimum cost to construct the rectangular box.

8 0
2 years ago
Consider the line segment below that is five feet long. Is Q the midpoint of PR? Justify your answer.
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Answer:

Q is not the midpoint of PR

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

If Q is the midpoint of PR

then

PQ=QR

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Remember that

PR=5\ ft ----> given problem

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