you would first have to multiply 20% by 3.24 and then youll get 0.648 then you subtract 3.24 by 0.648 and get 2.60. Then multiply 20% by 3.99 and get 0.798 then subtract 3.99 by 0.798 and get 3.19 then add 2.60 with 3.19 to get 5.79. 5.79 is how much she spent with 20% off
Answer:
see explanation
Step-by-step explanation:
(4)
consider the left side
factor the numerator
cosx - cos³x = cosx(1 - cos²x)
![\frac{cosx(1-cos^2x)}{sinx}[/tex = [tex]\frac{cosxsin^2x}{sinx}](https://tex.z-dn.net/?f=%5Cfrac%7Bcosx%281-cos%5E2x%29%7D%7Bsinx%7D%5B%2Ftex%20%3D%20%5Btex%5D%5Cfrac%7Bcosxsin%5E2x%7D%7Bsinx%7D)
cancel sinx on numerator/denominator
= cosxsinx =right side ⇒ verified
(5)
Consider the left side
expand the factors
(1 + cotΘ)² + (1 - cotΘ)²
= 1 + 2cotΘ + cot²Θ + 1 - 2cotΘ + cot²Θ
= 2 + 2cot²Θ
= 2(1 + cot²Θ) ← 1 + cot²Θ = cosec²Θ
= 2cosec²Θ = right side ⇒ verified
(6)
Consider the left side
the denominator simplifies to
cosxtanx = cosx × 
= sinx
= sinx( 
+ 
)
= + 
= tanx + 1 = right side ⇒ verified
Answer:
Option A is the important variable.
Step-by-step explanation:
Given is - At 9:45 a.m. a patient’s temperature was 101.5 degrees at 10:41, the nurse took the patients temperature again and found it was 105.8 degrees, the highest ever recorded.
The variable that is most important here is A: the number of minutes it took for the to reach its peak.
Firstly it is not mentioned if 10:41 is am or pm.
If its am, then such a temperature rise in less than an hour is very dangerous.
So, the important variable is option A.
We would need to look over the z table to find the area under the standard normal distribution curve to the left of z = 1.04. Then we'll subtract it from 1 to get the proportion of a normal distribution corresponding to z scores greater than 1.04.
By looking at the z table, we can see that the area to the left of z = 1.04 is 0.8508. So the proportion of a normal distribution to the right of z = 1.04 is 1 – 0.8508 = 0.1492.
The answer is 0.1492.
Answer:
Step-by-step explanation:
