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lutik1710 [3]
2 years ago
8

How to solve 52/48 in the form of hcf​

Mathematics
1 answer:
algol132 years ago
6 0

HCF is 4

Step-by-step explanation:

factors of 52 are: 2x2x13

factors of 48 are:2x2x2x2x3

common factors of 52%48 are: 2

hence, = 2x2

=4

hope it helps

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The graph of the continuous function g, the derivative of the function f, is shown above. The function g is piecewise linear for
4vir4ik [10]
A) g=f' is continuous, so f is also continuous. This means if we were to integrate g, the same constant of integration would apply across its entire domain. Over 0, we have g(x)=2x. This means that


f_{0


For f to be continuous, we need the limit as x\to1^- to match f(1)=3. This means we must have


\displaystyle\lim_{x\to1}x^2+C=1+C=3\implies C=2


Now, over x, we have g(x)=-3, so f_{x, which means f(-5)=17.


b) Integrating over [1, 3] is easy; it's just the area of a 2x2 square. So,


\displaystyle\int_1^6g(x)=4+\int_3^62(x-4)^2\,\mathrm dx=4+6=10


c) f is increasing when f'=g>0, and concave upward when f''=g'>0, i.e. when g is also increasing.

We have g>0 over the intervals 0 and x>4. We can additionally see that g'>0 only on 0 and x>4.


d) Inflection points occur when f''=g'=0, and at such a point, to either side the sign of the second derivative f''=g' changes. We see this happening at x=4, for which g'=0, and to the left of x=4 we have g decreasing, then increasing along the other side.


We also have g'=0 along the interval -1, but even if we were to allow an entire interval as a "site of inflection", we can see that g'>0 to either side, so concavity would not change.
5 0
3 years ago
Graph the equation.<br> y=5/17(x-1)(x-9)
Anni [7]

Answer:

Attached Image

Step-by-step explanation:

Vertex: (5, -5)

X-Intercepts: (1,0) (9,0)

Y-Intercepts: (0, 2.813)

hope this helps :)

7 0
2 years ago
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Ierofanga [76]

Answer:

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Step-by-step explanation:

When we multiply all of the d's together we get d^{24}.

4 0
3 years ago
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