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Fynjy0 [20]
3 years ago
6

A coin-operated machine sells plastic rings. It contains 11 orange rings, 15 green rings, 0 pink rings, and 5 yellow rings. Patr

icia puts a coin into the machine. Find the theoretical probability she gets a yellow ring. Express your answer as a decimal. If necessary, round your answer to the nearest thousandth
Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
3 0

Answer:

16.129

Step-by-step explanation:

11+15+5=31

5÷31=0.16129

0.16129x100

=16.129

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Tom [10]

can you translate it to engish, i might help!

7 0
3 years ago
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I need help with part b. I feel like there’s a catch, I want to do the first derivative test, however, I feel like there is a be
Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: g'(-1)\,(1) since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: g'(-1)= 7 as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1

6 0
3 years ago
Anyone please help me pleaseeee
lora16 [44]

R = { (x,y): 3x-y=0 }

The condition is 3x=y so that's not going to be any of these things.

R is reflexive if (x,x)∈R for all x.   Let's check.

3x - y = 3x - x = 2x ≠ 0  necessarily.   NOT REFLEXIVE

R is symmetric if (x,y)∈R → (y,x)∈R.   Let's check.

(x,y)∈R  so

3x-y = 0

y  = 3x

Is  (y,x)∈R.  That would be true if 3y-x=0

3y - x = 3(3x) - x = 8x ≠ 0 necessarily NOT SYMMETRIC

R is transitive if (x,y)∈R and (y,z)∈R → (x,z)∈R.   Let's check.

3x-y = 0  so y=3x

3y-z = 0 so z=3y = 9x

3x - z = 3x - 9x = -6x ≠ 0 necessarily   NOT TRANSITIVE

6 0
3 years ago
Suppose f(x) = x2 and g(x) = (3x)2. Which statement best compares the graph
Ksenya-84 [330]

Answer:

Step-by-step explanation:

Please use " ^ " to indicate exponentiation:  f(x) = x^2 and g(x) = (3x)^2.

g(x) can be rewritten as 9x^2.

The graph of g(x) is only one ninth as wide as that of f(x).

Next time please share the possible answer choices.  Thank you.

6 0
3 years ago
4. True or false: Lines, colors, and textures are often used to create shapes.
ioda

Answer:

true!

Step-by-step explanation:

because if we havent got lines, colors ,  and textures

how could shapes be created?

8 0
1 year ago
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