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katrin [286]
3 years ago
9

(practice quiz)subject: Mathematics ​

Mathematics
2 answers:
storchak [24]3 years ago
8 0
A leaky pool loses 2 1/4 inches of water each day. Jermaine and Mildred are asked to determine the change in the amount of water in the pool over 5 days.
Charra [1.4K]3 years ago
6 0

Answer:

80cm by 60cm

Step-by-step explanation:

For every inch is to 40 cm.

Length = 2in*40=80 cm

Width. =1.5in*40=60cm

You might be interested in
A box contains 11 red chips and 4 blue chips. We perform the following two-step experiment: (1) First, a chip is selected at ran
Scilla [17]

Answer:

P(B1) = (11/15)

P(B2) = (4/15)

P(A) = (11/15)

P(B1|A) = (5/7)

P(B2|A) = (2/7)

Step-by-step explanation:

There are 11 red chips and 4 blue chips in a box. Two chips are selected one after the other at random and without replacement from the box.

B1 is the event that the chip removed from the box at the first step of the experiment is red.

B2 is the event that the chip removed from the box at the first step of the experiment is blue. A is the event that the chip selected from the box at the second step of the experiment is red.

Note that the probability of an event is the number of elements in that event divided by the Total number of elements in the sample space.

P(E) = n(E) ÷ n(S)

P(B1) = probability that the first chip selected is a red chip = (11/15)

P(B2) = probability that the first chip selected is a blue chip = (4/15)

P(A) = probability that the second chip selected is a red chip

P(A) = P(B1 n A) + P(B2 n A) (Since events B1 and B2 are mutually exclusive)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/21) + (22/105) = (77/105) = (11/15)

P(B1|A) = probability that the first chip selected is a red chip given that the second chip selected is a red chip

The conditional probability, P(X|Y) is given mathematically as

P(X|Y) = P(X n Y) ÷ P(Y)

So, P(B1|A) = P(B1 n A) ÷ P(A)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(A) = (11/15)

P(B1|A) = (11/21) ÷ (11/15) = (15/21) = (5/7)

P(B2|A) = probability that the first chip selected is a blue chip given that the second chip selected is a red chip

P(B2|A) = P(B2 n A) ÷ P(A)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/15)

P(B2|A) = (22/105) ÷ (11/15) = (2/7)

Hope this Helps!!!

5 0
3 years ago
Will mark brainliest please show work
SVEN [57.7K]

Answer:

5/4

Step-by-step explanation:

7 0
3 years ago
HELP WITH PROBABILITY PWEASEEE <br> (4 questions)
Aliun [14]

a. {1,2,3,4,5,6}

b. {A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z}

c. {HH,HT,TH,TT}

d. {1T,2T,3T,4T,5T,6T,1H,2H,3H,4H,5H,6H}

Step-by-step explanation:

We will write the sample space of all options one by one.

a. Rolling a 6 sided die

As the die has six sides numbered from 1 to six then the sample space will be:

S1 =  {1,2,3,4,5,6}

b. Guessing the first initial of a student's name:

As the English language has 26 alphabets, the first initial can be any alphabet so the sample space will be all letters:

S2 =  {A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z}

c. Tossing two coins

As two coins are tossed, the outcomes will be a combination of two outcomes

S3= {HH,HT,TH,TT}

d. Rolling a 6 sided die and tossing a coin

As the die is rolled and then a coin is tossed. The die's coin will either combine with heads or tails

So,

S4 = {1T,2T,3T,4T,5T,6T,1H,2H,3H,4H,5H,6H}

Hence,

a. {1,2,3,4,5,6}

b. {A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z}

c. {HH,HT,TH,TT}

d. {1T,2T,3T,4T,5T,6T,1H,2H,3H,4H,5H,6H}

Keywords: Sample Space, Probability

Learn more about sample space at:

  • brainly.com/question/11007026
  • brainly.com/question/11207748

#LearnwithBrainly

8 0
4 years ago
Stella wants to buy colored pencils that cost $3.50. She has 1 dollar, 5 quarters, 4 dimes, and 7 pennies. Does she have enough
Andrews [41]

Answer:

no

Step-by-step explanation:

Lets she how much money she has

1.00   dollars

5 * .25 = 1.25 quarters

4 * .10 = .40 dimes

7 * .01 = .07 pennies

Add it all together

1 + 1.25+ .40 +.07 =2.72

3.50 - 2.72 =.78

She is 78 cents short

6 0
3 years ago
Tristan is working two summer jobs, making $7 per hour babysitting and $19 per hour lifeguarding. Tristan must earn at least $21
rodikova [14]

Answer: 7bb +19 ll ≥210

Step-by-step explanation:

Hi, to answer this question we have to write an inequality:

The product of the number of hours he works babysitting (bb) and the amount he earns per hour (7); plus The product of the number of hours he works lifeguarding (ll) and the amount he earns per hour 19; must be higher or equal to the amount he must earn this week (210)

Mathematically speaking:

7 bb + 19 ll ≥210

6 0
3 years ago
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