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Igoryamba
3 years ago
13

62 divided by 3 times 2 + 4

Mathematics
2 answers:
nadezda [96]3 years ago
5 0
45.33333333 (recurring)
Bumek [7]3 years ago
4 0
This question is unsolvable unless you provide the actual equation, as this could mean:
62/3 x (2 + 4) or,
62/(3 x (2 + 4)) or,
(62/3 x 2) + 4
or a number of other arrangments of the equation, all of which will give different answers. If you can provide an actual mathematical equation, I can help, but otherwise these words mean nothing
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What does x = in this equation x+3+2x=x+5
Ede4ka [16]

Answer:

X would be equal to 1

Step-by-step explanation:


5 0
4 years ago
Read 2 more answers
Plsssssssssss help me!!! I’m not good at algebra!!
Elza [17]

Answer:

x=50

Step-by-step explanation:

This is a vertical angle, so the angle on top and the bottom are equal

[2(x+10)]=3x-30

2(x+10)=3x-30

2x+20=3x-30

50=x

8 0
3 years ago
Write the quadratic equation with the given roots 3 and -2/3
trapecia [35]

<em>Answer: </em>

<em>y  =  </em>x^{2}<em> −  7  x  3  − 2</em>

<em />

<em>Step-by-step explanation:</em>

<em>you gotta work backwards to find the factors from the roots then multiply the factors together.</em>

7 0
3 years ago
Let f be a function defined for t ≥ 0. Then the integral ℒ{f(t)} = [infinity] e−stf(t) dt 0 is said to be the Laplace transform
sveticcg [70]

Answer:

L(f(t)) = 2 \frac{e^{-s} }{s} - \frac{1}{s}

Step-by-step explanation:

let f be a function defined for t ≥ 0

we can write the function f(t) in terms of unit function as follows

f(t) = 2 u,(t) - 1  where

      0≤ t < 1

f(t) = (2 * 0) -1 = -1

when t ≥ 1

f(t) = (2*1 )- 1 = 1

Now the Laplace transform L(F(T)) = 2L( u, (t) ) - L(1)  --------equation 1

this is because L(u,(t)) = \frac{e^{-cs} }{s}

c = 1 hence L(1) = 1/s

back to equation 1

L(f(t)) = 2 \frac{e^{-cs} }{s} -  1/s  laplace transform

also L(u(t) ) = \frac{e^{-s} }{s}

3 0
3 years ago
3. The range of (x) = 2(x - 1) - 6 is
just olya [345]

Answer:d

Step-by-step explanation:

3 0
3 years ago
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