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3 years ago

Solve the following expression when t = 6 and d = 8 t + d = 8 - 6

Mathematics

1 answer:

Anna [14]3 years ago

6 0

Answer:

Hi! Your answer is 14 = 2

Step-by-step explanation:

Evaluate

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A trade magazine routinely checks the drive-through service times of fast-food restaurants. Upper AA 9595% confidence interva

Butoxors [25]

Answer:

One can be 95% confident that the drive-through service times of fast-food chain is between 169 seconds and 172 seconds.

Step-by-step explanation:

The confidence interval gives a range of value for the population mean or parameter, which is calculated from the statistic value of the data (that is sample statistic). This range gives the interval which is associated with a certain level of confidence for which the interval will contain the true value of the unknown parameter (true value). In the scenario above, the associated confidence level is 95%.Hence, we can be 95% confident that the true value will be continued with the interval (169 ; 172)

6 0

3 years ago

Find the solution to the system. Write your solution as an ordered pair (x,y)

Studentka2010 [4]

Answer:

Infinitely many

Step-by-step explanation:

If we multiply the equation x-3y=7 by 3, we get 3x-9y=21, which is also the second equation. That means the two lines are on top of each other, meaning infinite many solutions.

3 0

3 years ago

How do I begin to factor 3p2-2p-5

Scilla [17]

$3p^2-2p-5=3p^2+3p-5p-5=3p(p+1)-5(p+1)\\\\=\boxed{(p+1)(3p-5)}$

4 0

3 years ago

Two faulty machines, M1 and M2, are repeatedly run synchronously in parallel (i.e., both machines execute one run, then both exe

leonid [27]

The event that either M1 or M2 fails has probability

$P(M_1\text{ fails or }M_2\text{ fails})=P(M_1\text{ fails})+P(M_2\text{ fails})-P(M_1\text{ and }M_2\text{ both fail})$

by the addition rule. Failure events are independent, so

$P(M_1\text{ and }M_2\text{ both fail})=P(M_1\text{ fails})P(M_2\text{ fails})$

so that

$P(M_1\text{ fails or }M_2\text{ fails})=p_1+p_2-p_1p_2$

Denote this probability by $p$ . Then $X$ follows a geometric distribution with this parameter $p$ and has density

$P(X=x)=\begin{cases}(1-p)^{x-1}p&\text{for }x\ge1\\0&\text{otherwise}\end{cases}$

The expectation is $\dfrac1p=\dfrac1{p_1+p_2-p_1p_2}$ .

7 0

4 years ago

For some unknown function f(x), we are told that lim x --> 0 ( f(x)-3 ) / 5x = 7

Viktor [21]

$\bf \lim\limits_{x\to 0}\ \cfrac{f(x)-3}{5x}=7\\\\
-----------------------------\\\\
 \cfrac{f(x)-3}{5x}=7\implies f(x)-3=35x\implies \boxed{f(x)=35x+3}\\\\
-----------------------------\\\\

\lim\limits_{x\to 0}\ \cfrac{\boxed{35x+3}-3}{5x}\implies \cfrac{35x}{5x}\implies 7$

7 0

4 years ago