A total of 6.54 inches of snow fell during a storm. The snow fell at an

What is the answer for this math 4- -13=!

Flauer [41]

4 - (-13) = 17

Hope this helps!

6 0

3 years ago

Passing through (2, - 2) and perpendicular to the line whose equation is y= 5x+2

jonny [76]

Step-by-step explanation:

Hey there!!!

Here,

Given, A line passes through point (2,-2) and is perpendicular to the y= 5x+2.

The equation of a straight line passing through point is,

$(y - y1) = m1(x - x1)$

Now, put all values.

$(y + 2) = m1(x - 2)$

It is the 1st equation.

Another equation is;

y = 5x +2........(2nd equation).

Now, Comparing it with y = mx + c, we get;

m2=5

As per the condition of perpendicular lines,

m1×m2= -1

m1 × 5 = -1

Therefore, m2= -1/5.

Keeping the value of m1 in 1st equation.

$(y + 2) = \frac{ - 1}{5} (x - 2)$

Simplify them.

$5(y + 2) = - x + 2$

$5y + 10 = - x + 2$

$x + 5y + 8 = 0$

Therefore the required equation is x+5y+8= 0.

Hope it helps...

7 0

3 years ago

Please answer the question from the attachment.

levacccp [35]

You just take 1000 and multiply it by .05. Its 50mL.

4 0

3 years ago

What is the solution to the system of two equations shown?

Nadya [2.5K]

The solution of the given system of equation is x = -3 and y = 4 respectively.

<h3>What is a system of linear equations?</h3>

A system of linear equations can be defined as a number of equations needed to solve the equations. For n number of variables n number of equations are required.

The given system of equations is as,

y = 4x + 16 (1)

y = −2x − 2 (2)

In order to solve them, substitute equation (2) into (1) as follows,

4x + 16 = −2x − 2

=> 4x + 2x = -2 - 16

=> 6x = -18

=> x = -3

Then, y = -2 × -3 - 2 = 4

Hence, the solution of the given system of equation is x = -3 and y = 4.

To know more about system of equations click on,

brainly.com/question/24065247

#SPJ1

6 0

1 year ago

The branch manager of an outlet (Store 1) of a nationwide

monitta

Answer:

1. ( 19.1416, 23.5384,)

2. (0.276348, 0.46651)

3. the sample size = 170.73 approximately 171

4. sample size = 334.07 approximately 334

5. sample of 334 should be taken by manager

Step-by-step explanation:

mean = bar x = 21.34 dollars

size of sample n = 70

standard deviation of sample = 9.22

we use t distribution as the population standard deviation is not known.

95% Confidence interval

1-α = 0.95

α = 0.05

degree of freedom = 70-1 = 69

α/2 = 0.025

using the t distribution tsble,

= 1.9949

confidence interval = $21.34+-1.9949*[\frac{9.22}{sqrt(70)}] \\$

= 21.34 +- (1.9949*1.10200)

= 21.34 + 2.1984, 21.34 - 2.1984

= (23.5384, 19.1416)

the confidence interval of the mean amount spent at the supply store can be written as 19.1416<u<23.5384

2. sixe of those who only have a cat

p = 26/70 = 0.371429

at 90 % confidence interval,

1-α = 0.90

α = 0.10

we use the z table here

z(0.10/2) = Z(0.05)

= 1.645

$0.371429+-1.645\sqrt} \frac{0.371429(1-0.371429)}{70}$

= 0.371429 +-( 1.645 x 0.0578)

= 0.371429 + 0.095081, 0.371429 - 0.095081

= (0.276348, 0.46651)

3. sd = 10$

margin of erro,r e = 1.50$

α = 0.05

using z table

α/2 = Z0.025

= 1.96

sample size = 1.96² * 10² / 1.50²

= 3.8416 * 100/ 2.25

= 170.73

the sample size is approximately 171

d. we have 0.5 as sample proportion now

margin of error = 0.045

α = 0.10

Zα/2 = 0.05

= 1.645

sample size = 1.645²x0.5(1-0.5) / 0.045²

= 0.676506/0.002025

= 334. 07

sample size = 334

5. sample of 334 should be taken by manager

3 0

3 years ago