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Aleks04 [339]
3 years ago
13

PLEASEEEE HELPPPP IF CORRECT I WILL MARK YOU BRAINLIEST

Mathematics
1 answer:
Tems11 [23]3 years ago
5 0
810in2
REMEMBER
Area of triangle is (base times height divided by 2)
Area on rectangle is length times height
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2/3 is less than 4/5 true or false
mojhsa [17]

Answer: False

Step-by-step explanation:

When comparing fractions such as 2/3 and 4/5, you could also convert the fractions (if necessary) so they have the same denominator and then compare which numerator is larger.

6 0
3 years ago
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A rectangular prism has a base area of 2 square feet and a height of 5 feet. What
kvasek [131]
11 cubic feet is the answer
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Jethro walked at an average speed of 3 miles per hour for 2 hours. Randy walked at an average of 4 miles per hour for 3 hours. W
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IS the answer
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3 years ago
Find the equation of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit.
leonid [27]

<u>Answer-</u>

The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

12x-5y+14=0 \\ 12x-5y-14=0

<u>Solution-</u>

Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)

The applying the distance formula,

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{12^2+5^2}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{169}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{13} \right |=1

\Rightarrow 12h-5k-1=\pm 13

\Rightarrow 12h-5k=\pm 14

\Rightarrow 12h-5k=14,\ 12h-5k=-14

\Rightarrow 12h-5k-14=0,\ 12h-5k+14=0

\Rightarrow 12x-5y-14=0,\ 12x-5y+14=0

Two equations are formed because one will be upper from the the given line and other will be below it.

4 0
3 years ago
The furniture store where Jada's sister works bought a table for $200 and sold it for $350. What percentage was the markup? I wa
nevsk [136]

Answer:

divide 350 by 200

Step-by-step explanation:

3 0
3 years ago
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