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3 years ago

A figure composed of two quadrilaterals is shown.

Mathematics

1 answer:

Tems11 [23]3 years ago

6 0

Answer:

D a reflection over a line through point P followed by a dilation centered at point P

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A recipe needs 3/4 cup of sugar.if the recipe is doubled how much sugar is needed

Elina [12.6K]

Answer:

Step-by-step explanation:

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4 years ago

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What is 452 to the nearest thousand

son4ous [18]

The next larger even thousand is 1,000 .

The next smaller even thousand is zero thousands.

452 is nearer to <em>zero</em> thousand than it is to 1,000 .

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3 years ago

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What is the rule for the sequence<br>5/6, 1 1/2, 2 1/6, 2 5/6.....

photoshop1234 [79]

First term: a: 5/6
2nd term: 3/2 = 9/6
3rd term: 13/6
4th term: 17/6

a(n+1)=a(n) + 4/6, or a(n+1) = a(n) + 2/3, with a(1) = 5/6

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4 years ago

SOLVE THIS PLS JSJSXHHX

madam [21]

Step-by-step explanation:

y = ax + b

I see already the result (y = x/10 × 1/6), but let's go in formally.

we have multiple function points to use to officially calculate a and b.

1/6 = a×10 + b

2/3 = a×40 + b

5/6 = a×50 + b

1 2/3 = a×100 + b

let's e.g subtract equation 1 from equation 3.

4/6 = a×40 + 0

a = 4/40 / 6 = 4 / 240 = 1/60

1/6 = 10/60 + b

1/6 = 1/6 + b

b = 0

so, the function is

y = x/60

x = 25

y = 25/60 = 5/12 cups

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3 years ago

Which trigonometric ratios are correct for triangle ABC? Check all that apply

sergij07 [2.7K]

Consider an angle M with measure m≠90°, in a right triangle.

Let

OPP denote the length of the side opposite to M,
ADJ denote the length of the side adjacent to M, and
HYP denote the hypotenuse.

then:

Sin(M) = OPP/HYP
Cos(M)= ADJ/HYPP
Tan(M)=OPP/ADJ

Back to our problem,

using the Pythagorean we can find the length of AB:

$|AB|^2+|AC|^2=|BC|^2\\\\|AB|^2+9^2=18^2\\\\|AB|^2=18^2-9^2\\\\|AB|^2=(18-9)(18+9)=9 \cdot 27=9 \cdot 9 \cdot3\\\\|AB|=9 \sqrt{3} 
$

$Sin(C)= \frac{OPP}{HYP}=\frac{9 \sqrt{3} }{18}= \frac{ \sqrt{3} }{2}$
$Cos(B)= \frac{ADJ}{HYP}= \frac{9 \sqrt{3}}{18}= \frac{ \sqrt{3}}{2}$
$Tan(C)= \frac{OPP}{ADJ}= \frac{9 \sqrt{3} }{9}= \sqrt{3}$
$Sin(B)= \frac{OPP}{HYP}= \frac{9}{18}= \frac{1}{2}$
$Tan(B)= \frac{OPP}{ADJ}= \frac{9}{9 \sqrt{3}}= \frac{1}{ \sqrt{3} }= \frac{ \sqrt{3}}{3}$

Answer: 1, 3, 4

5 0

3 years ago