Are the triangles congruent? If so, name the postulate or theorem that

Need help with math lesson please

LekaFEV [45]

Am I supposed to look at letter a or b or c or d ?

7 0

3 years ago

PLease Help Me [99 points]

xxTIMURxx [149]

A graph is a function if there is only one X value for any Y value.

Since the graph is in the shape of a U, there can only be one X for every Y value, so this graph is a function.
The answer is C.

6 0

3 years ago

Read 2 more answers

MAT-144-0502

Katena32 [7]

Answer:

5

Step-by-step explanation:

8 0

3 years ago

The path of a race will be drawn on a coordinate grid like the one shown below. The starting point of the race will be at (−5.3,

m_a_m_a [10]

The Cartesian coordinate plane, specify locations by a pair of coordinates that indicate the magnitude in perpendicular, x, and y directions

The correct responses are;

Part A: The starting point is in the second quadrant and the finishing point is in the fourth quadrant.

Part B: The starting point and the check point are on different quadrant. Both points are on the same horizontal line.

Reasons:

The location of the start point of the race = (-5.3, 1)

Location of the finishing point = (1, -5.3)

Part A: The signs of the x and y-values in the quadrants are;

$\begin{tabular}{|cc|c|}Quad II, x -ve, y +ve&&Quad I, x, and y are +ve\\&&\\Quad III, x -ve, y -ve&&Quad IV, x +ve, y -ve\end{array}\right]$

The coordinates of the starting point is (-5.3, 1), therefore, given that the x-

coordinate is negative and the y-coordinate is positive, the quadrant of the

starting point is quadrant II (the second quadrant).

The quadrant of the starting point is the second quadrant.

The coordinates of the finishing point is (1, -5.3), the x-value is positive and

the y-value is negative, which indicates that the quadrant of the finishing

point is quadrant IV (the fourth quadrant).

The quadrant of the finishing point is the fourth quadrant.

Part B: The location of the checkpoint is; (5.3, 1)

The difference is that the x-value of the checkpoint is positive while the x-value of the starting point is negative, and they are therefore on different quadrants.

The similarity is that, the magnitude of the x, and y values of the coordinates of the check point and the starting point are the same. Therefore, the checkpoint and the starting point are on the same horizontal line.

Learn more about the Cartesian coordinate plane here:

brainly.com/question/17877300

brainly.com/question/16177011

8 0

3 years ago

In quadrilateral ABCD, BN and DM are drawn perpendicular to AC such that BN = DM. Prove that O is the midpoint of BD

GaryK [48]

Answer:

Step-by-step explanation:

Given :

In the given quadrilateral ABCD,

BN and DM are the perpendiculars drawn to AC such that,

BN = DM

To prove:

Point O is the midpoint of segment BD.

Or

OD = OB

Solution:

In ΔOMD and ΔONB,

∠MOD ≅ NOB [Vertical angles]

∠M ≅ ∠N ≅ 90° [Given]

Therefore, by AA property of similarity,

ΔOMD ~ Δ ONB

Therefore, their corresponding sides will be proportional,

$\frac{DM}{BN}=\frac{OD}{OB}$

Since BN = DM,

OD = OB

Hence O is the midpoint of BD.

4 0

4 years ago