What is the value of y for the point with an x-value of 5?

Joe biked the following distances this past week to train for a triathlon. Joe biked 37 miles, 88 miles, 44 miles, 54 miles, 62

Artyom0805 [142]

Answer:

The median is 50.

Step-by-step explanation:

First you put all the numbers in order. (37, 44, 46, 54, 62, 88) then you look for the middle number. Since there is two middle numbers, you add them together then divide it by 2.

So 46+54= 100

100/2= 50

8 0

3 years ago

8.6E-10 in standard form

Afina-wow [57]

65 is the asnwer hope i helped

6 0

4 years ago

Is 97 an irrational number?

user100 [1]

Answer:

No 97 is not an irrational number 

Step-by-step explanation:

Be happy

7 0

3 years ago

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Physics students were modeling the height of a ball once it was dropped from the top of a 10 foot ladder. The

julsineya [31]

Answer:

Interval notation: [0, 2.236]

Set Builder notation: $\{t\ |\ 0\le t\le 2.236\}$

Step-by-step explanation:

Given that:

Equation of height of the ball dropped from a height of 10 foot, as:

$h(t) = 10 - 2t^2$

Where $t$ is the time since the ball was dropped.

To find:

The domain of the function in Interval and set builder notation.

Solution:

Domain of a function is defined as the set of valid input values that can be given to the function for which the function is defined.

Here, input is time.

We can not have negative values for time.

Therefore, starting value for time will be 0 seconds.

And the value of height can not be lesser than that of 0 ft.

$0= 10 - 2t^2\\\Rightarrow 2t^2=10\\\Rightarrow t^2=5\\\Rightarrow t =2.236\ seconds$

Maximum value for time can be 2.236 seconds.

Therefore the domain is:

Interval notation: [0, 2.236]

Set Builder notation: $\{t\ |\ 0\le t\le 2.236\}$

4 0

3 years ago

Josephine has a rectangular garden with an area of 2x2

sergeinik [125]

Answer:

Fourth example, (2x - 3) and (x + 2), are possible dimensions

Step-by-step explanation:

Let's go through all the responses one by one;

First of all the area of the rectangular garden can be computed through length times width, such that:

(x^2 - 3) * (2) = 2x^2 + x - 6,

(2x + 3) * (x-2) = 2x^2 + x - 6,

(2x + 2) * (x-3) = 2x^2 + x - 6,

(2x - 3) * (x + 2) = 2x^2 + x - 6

Now in each of these examples, it should be that the products are equivalent to the area according to the length by width rule, so let's see which is truly the correct dimensions by justifying whether the product is truly equivalent to the area.

First example:

2 * (x^2 - 3) = 2x^2 - 6

Now 2x^2 - 6 ≠ 2x^2 + x - 6 so the first example is not a possibility,

Second example:

(2x + 3) * (x-2) = 2x^2- x - 6

Now 2x^2- x - 6 ≠ 2x^2 + x - 6 so the second example is not a possibility,

Third example:

(2x + 2) * (x-3) = 2x^2 - 4x - 6

Now 2x^2 - 4x - 6 ≠ 2x^2 + x - 6 so the third example is not a possibility,

Fourth example:

(2x - 3) * (x + 2) = 2x^2 + x - 6

Here 2x^2 + x - 6 = 2x^2 + x - 6 so the fourth example can act as possible dimensions

6 0

3 years ago

Read 2 more answers